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bezimeni [28]
2 years ago
8

21. Margo worked 95.25 hours in 15 days. What is the average amour

Mathematics
1 answer:
Katarina [22]2 years ago
4 0

Answer:

6.35

Step-by-step explanation:

since we're trying to find the amount she worked <em>each</em> day, we have to divide.

95.25/15 = 6.35

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Rewrite in simplest radical form <br> 1/x^−3/6<br> Show each step of your process please!
Romashka [77]
\frac{1}{a^{-b} } =a^b \\c^{ \frac{a}{b} }= \sqrt[b]{c^a}  \\   \\  \frac{1}{x^{- \frac{3}{6} }}=\frac{1}{x^{- \frac{1}{2} }} =x^ \frac{1}{2} = \sqrt[2]{x^1} = \sqrt{x}
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3 years ago
What is the least common multiple of 15 and 8?
Arturiano [62]
O get the Least Common Multiple (LCM) of 15 and 8 we need to factor each value first and then we choose all the factors which appear in any column and multiply them: 

<span><span>15:      35</span><span>8:   222  </span><span>LCM:   22235</span></span>

<span>The Least Common Multiple (LCM) is:   2 x 2 x 2 x 3 x 5 = 120</span>

5 0
3 years ago
Read 2 more answers
Sophia pays £222 for a plane ticket.
Maurinko [17]

9514 1404 393

Answer:

  24.6%

Step-by-step explanation:

The cost of the ticket in euros is ...

  £222 × €1.38/(£1) = €306.36

Then the ratio of the tax to the to the total cost is ...

  €100/(€306.36 +100) = 100/406.36 ≈ 24.6%

6 0
2 years ago
in your class,0.58 of students bring a piece of while fruit for s snack and 0.36 of the students bring a snack pack of crackers.
scZoUnD [109]

Answer: S snacks


Step-by-step explanation:


8 0
3 years ago
There are premium tickets costing $99 each and rest are regualr tickets costing $25 each. A pile of 120 tickets have a total val
polet [3.4K]

Answer:

There are 38 premium tickets and 82 regular tickets in a pile.

Step-by-step explanation:

Given,

Total number of tickets = 120

Total amount = $5812

Solution,

Let the number of premium tickets be x.

And the number of regular tickets be y.

Total number of tickets is the sum of total number of premium tickets and  total number of regular tickets.

So the equation can be written as;

x+y=120\ \ \ \ \ equation\ 1

Again,total amount  is the sum of total number of premium tickets multiplied by cost of each premium ticket and  total number of regular tickets multiplied by cost of each regular ticket.

So the equation can be written as;

99x+25y=5812\ \ \ \ equation\ 2

Now We will multiply equation 1 by 25 we get;

x+y=120\\25(x+y)=120\times25\\25x+25y= 3000 \ \ \ \ equation\ 3

Now Subtracting equation 3 from equation 2 we get;

(99x+25y)-(25x+25y)=5812-3000\\\\99x+25y-25x-25y=2812\\\\74x=2812\\\\x=\frac{2812}{74}=38

We will now substitute the value of x in equation 1 we get;

x+y=120\\38+y=120\\y=120-38\\y=82

Hence There are 38 premium tickets and 82 regular tickets in a pile.

3 0
3 years ago
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