Find a real number between -3 and 5 a : -4 b : 1 c : -5 d : 6
1 answer:
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Answer:
Question 4:
Question 5:
Step-by-step explanation:
Hi there!
Linear equations are typically organized in slope-intercept form: where <em>m</em> is the slope of the line and <em>b</em> is the y-intercept (the y-coordinate of the point where the line crosses the y-axis).
<u>Question 4</u>
<u>1) Determine the slope (</u><u><em>m</em></u><u>)</u>
where two points that pass through the line are
and
In the graph, two easy-to-identify points on the line are (-5,4) and (5,-4). Plug these into the equation:
Therefore, the slope of the line is . Plug this into
as the slope (<em>m</em>):
<u>2) Determine the y-intercept (</u><u><em>b</em></u><u>)</u>
On the graph, we can see that the line crosses the y-axis when y is 0. Therefore, the y-intercept (<em>b</em>) is 0. Plug this into :
<u>Question 5</u>
<u>1) Determine the slope (</u><u><em>m</em></u><u>)</u>
Two easy-to-identify points are (-1,2) and (0,-3). Plug these into the equation:
Therefore, the slope is -5. Plug this into :
<u>2) Determine the y-intercept (</u><u><em>b</em></u><u>)</u>
On the graph, we can see that the line crosses the y-axis at the point (0,-3). The y-coordinate of this point is -3. Therefore, the y-intercept (<em>b</em>) is -3. Plug this into :
I hope this helps!
