We can readily know the x^2-4x+4=3y then use it to replace the same function in the first equation which refers to the 3y+y^2-6y=0
y^2-3y=0
y(y-3)=0
y1=0 -----------y2=3
A quadratic function is given by y = ax^2 + bx + c
c(2) = a(2)^2 + 2b + c = 45
4a + 2b + c = 45 . . . (1)
c(4) = a(4)^2 + 4b + c = 143
16a + 4b + c = 143 . . . (2)
c(10) = a(10)^2 + 10b + c = 869
100a + 10b + c = 869 . . . (3)
Solving (1), (2) and (3) gives a = 9, b = -5, c = 19
Therefore, c(x) = 9x^2 - 5x + 19
c(7) = 9(7)^2 - 5(7) + 19 = 9(49) - 35 + 19 = 441 - 16 = 425
Therefore, it costs $425 to produce 7 calculators.
-2/5x -2= 18
-2/5x=18+2
Divide -2/5 with both sides
x= -50
Answer:
12
Step-by-step explanation:
Since they are parallel then
(7x - 8) + (11x - 28) = 180
18x - 36 = 180
18x = 216
x = 12
Answer:
h = 3
Step-by-step explanation:
Step 1: Write out equation
(6h + 8) - (3h + 2) = 15
Step 2: Distribute negative
6h + 8 - 3h - 2 = 15
Step 3: Combine like terms
3h + 6 = 15
Step 4: Subtract 6 on both sides
3h = 9
Step 5: Divide both sides by 3
h = 3
Step 6: Check Step
(6(3) + 8) - (3(3) + 2) = 15
(18 + 8) - (9 + 2) = 15
26 - 11 = 15
15 = 15
