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Contact [7]
3 years ago
5

Use two unit multipliers to convert 600 miles to inches. ( Do not multiply out.)

Mathematics
1 answer:
Sphinxa [80]3 years ago
5 0

Answer:

(600 mi) × (5280 ft/mi) × (12 in/ft)

Step-by-step explanation:

A "unit multiplier" is a multiplier that has a value of 1. That is, the numerator and denominator have the same value. For units conversion problems, the numerator quantity has the units you want, and the denominator quantity has the units you're trying to cancel.

You have units of miles. You know that ...

1 mile = 5280 feet

1 foot = 12 inches

You want to get to units of inches. With these conversion factors, you can do it in two steps (as the problem requests). The first conversion is from miles to feet using the unit multiplier (5280 feet)/(1 mile). This gives you a number of feet.

Then the second conversion is from feet to inches, so you use the one that lets you put inches in the numerator and feet in the denominator:

(12 inches)/(1 foot)

When you multiplie these all out, units of miles and feet cancel, and you're left with inches.

_____

With the above conversion factors, you can write unit mulipliers of either ...

(5280 ft)/(1 mi) . . . to convert to feet

or

(1 mi)/(5280 ft) . . . to convert to miles.

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Write out the first four terms of the series to show how the series starts. Then find the sum of the series or show that it dive
Nostrana [21]

Answer:

The first four terms of the series are

(9+3),(\frac97+\frac35),(\frac9{7^2}+\frac3{5^2}),(\frac9{7^3}+\frac3{5^3})

\sum_{n=0}^\infty \frac9{7^n}+\frac{3}{5^n} = 14.25

Step-by-step explanation:

We know that

Sum of convergent series is also a convergent series.

We know that,

\sum_{k=0}^\infty a(r)^k

If the common ratio of a sequence |r| <1 then it is a convergent series.

The sum of the series is \sum_{k=0}^\infty a(r)^k=\frac{a}{1-r}

Given series,

\sum_{n=0}^\infty \frac9{7^n}+\frac{3}{5^n}

=(9+3)+(\frac97+\frac35)+(\frac9{7^2}+\frac3{5^2})+(\frac9{7^3}+\frac3{5^3})+.......

The first four terms of the series are

(9+3),(\frac97+\frac35),(\frac9{7^2}+\frac3{5^2}),(\frac9{7^3}+\frac3{5^3})

Let

S_n=\sum_{n=0}^\infty \frac{9}{7^n}    and     t_n=\sum_{n=0}^\infty \frac{3}{5^n}

Now for S_n,

S_n=9+\frac97+\frac{9}{7^2}+\frac9{7^3}+.......

    =\sum_{n=0}^\infty9(\frac 17)^n

It is a geometric series.

The common ratio of S_n is \frac17

The sum of the series

S_n=\sum_{n=0}^\infty \frac{9}{7^n}

    =\frac{9}{1-\frac17}

    =\frac{9}{\frac67}

    =\frac{9\times 7}{6}

    =10.5

Now for t_n

t_n= 3+\frac35+\frac{3}{5^2}+\frac3{5^3}+.......

    =\sum_{n=0}^\infty3(\frac 15)^n

It is a geometric series.

The common ratio of t_n is \frac15

The sum of the series

t_n=\sum_{n=0}^\infty \frac{3}{5^n}

    =\frac{3}{1-\frac15}

    =\frac{3}{\frac45}

    =\frac{3\times 5}{4}

    =3.75

The sum of the series is \sum_{n=0}^\infty \frac9{7^n}+\frac{3}{5^n}

                                        = S_n+t_n

                                       =10.5+3.75

                                       =14.25

4 0
4 years ago
Given h(x) = -2- 4, find h(-6)
likoan [24]

Answer:

h(-6) = 2

Step-by-step explanation:

-x - 4 =

-(-6) - 4 = 2

6-4=2

5 0
3 years ago
Please help this is confusing.
Makovka662 [10]

Answer:

The mashi e drilled down 45 feet. So -45

Step-by-step explanation:

72 = 24h

X = 15h

24x = 1080

x = 45

7 0
3 years ago
2(3p+4)–<br> 2<br> 3<br> p=<br> 1<br> 3<br> (9+p)
Rus_ich [418]

Answer:

6p + 8

Step-by-step explanation:

4 0
3 years ago
Cual es el resultado de factorizar la expresion (-x⁴+ 25x²)
Fittoniya [83]

Al factorizar la expresión dada obtenemos que es igual a x²*(5 - x)*(5 + 5)

Por propiedad de los números reales: tenemos que para a y b dos números reales, se cumple que:

(a² - b²) = (a + b)*(a - b)

Por lo tanto como tenemos: - x⁴ + 25x², ordenamos:

- x⁴ + 25x² = (25*x² - x⁴ = ((5x)² - (x²)²)

Usando la propiedad dada inicialmente: obtenemos que:

((5x)² - (x²)²) = (5x - x²)*(5x + x²)

Sacamos de cada término un factor común "x":

x*(5 - x)*x*(5 + x) = x²*(5 - x)*(5 + 5)

Puedes visitar: brainly.lat/tarea/12523641

4 0
3 years ago
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