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finlep [7]
3 years ago
7

Helpppppppppppppppppppppppppp

Mathematics
2 answers:
slavikrds [6]3 years ago
8 0
An even function is symmetric with respect to the y-axis. One way to identify an even function is to check the exponents of its terms, all of which must be even. For constants, we assume the exponent is zero (still considered an even number for this purpose). The first function will have an odd exponent because the expansion has a 2x term. The second function has 8x, which is also an odd exponent of 1. The third function has an odd exponent in x.
The fourth function is just a constant (with exponent 0), so it is an even function.
Artemon [7]3 years ago
5 0
An function is considered to be an even function only if f(-x) = f(x)
1. f(x) = (x-1)^2 = x^2 - 2x + 1
f(-x) = (-x-1)^2 = x^2 + 2x + 1
These two don't match, not an even function

2. f(x) = 8x
f(-x) = -8x
These two don't match, not an even function

3. f(x) = x^2 - x
f(-x) = (-x)^2 - (-x) = x^2 + x
These two don't match, not an even function

4. f(x) = 7
f(-x) = 7
Match, is an even function
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Vsevolod [243]
Take 8 times 4.9 and 8 times 3.7, 8 times 4.9 is 39.2 and 8 times 3.7 is 29.6 now all you have to do is subtract them numbers from each other and it gives you the answer of 9.6


Answer: 9.6
7 0
3 years ago
Jason and Britton are driving to St. George. Jason got a 20 mile head start and drove an
harina [27]

Answer:

  2 hours, 150 miles

Step-by-step explanation:

The relation between time, speed, and distance can be used to solve this problem. It can work well to consider just the distance between the drivers, and the speed at which that is changing.

<h3>Separation distance</h3>

Jason got a head start of 20 miles, so that is the initial separation between the two drivers.

<h3>Closure speed</h3>

Jason is driving 10 mph faster than Britton, so is closing the initial separation gap at that rate.

<h3>Closure time</h3>

The relevant relation is ...

  time = distance/speed

Then the time it takes to reduce the separation distance to zero is ...

  closure time = separation distance / closure speed = 20 mi / (10 mi/h)

  closure time = 2 h

Britton will catch up to Jason after 2 hours. In that time, Britton will have driven (2 h)(75 mi/h) = 150 miles.

__

<em>Additional comment</em>

The attached graph shows the distance driven as a function of time from when Britton started. The distances will be equal after 2 hours, meaning the drivers are in the same place, 150 miles from their starting spot.

3 0
1 year ago
Each student earns 3/4 point for every bonus question. If a student gets 6 bonus points, how many bonus questions did a student
klio [65]

Answer:

8

Step-by-step explanation:

6 divided by.75 if u think I'm wrong check and correct me

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kati45 [8]
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Step-by-step explanation:

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