Answer:
1/2 ^w : decay factor after w weeks
hope this helps
Step-by-step explanation:
Hello,
Here is your answer:
The proper answer to this question is option D "4.19%".
Your answer is D.
If you need anymore help feel free to ask me!
Hope this helps!
Outliers are data that are in a very far distance from other values in a set of data
Once an outlier is detected in a set of data, we can do the following to them:
- Discard the outlier
- Change the value of the outlier with another value within close range
- Consider the distribution given
We may have a set of data where some of the <em>values are far in distance from the majority of the data</em>. The set of such data are known as an outlier.
For example, give the set of data;
45 can be considered as an outlier since the <em>distance of data</em><em> to all other data is</em><em> large</em><em>.</em>
Once an outlier is detected in a set of data, we can do the following to them:
- Discard the outlier
- Change the value of the outlier with another value within close range
- Consider the distribution given
Learn more here: brainly.com/question/23258173
Answer:
A
Step-by-step explanation:
Sum the product of the components in the first row of A with the corresponding components of the first column in B
Repeat this with the components in the second row of A with the corresponding components of the second column in B, that is
AB
=
![\left[\begin{array}{ccc}3&1\\5&2\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%261%5C%5C5%262%5C%5C%5Cend%7Barray%7D%5Cright%5D)
= ![\left[\begin{array}{ccc}2(3)+1(5)&2(1)+1(2)\\3(3)+4(5)&3(1)+4(2)\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%283%29%2B1%285%29%262%281%29%2B1%282%29%5C%5C3%283%29%2B4%285%29%263%281%29%2B4%282%29%5C%5C%5Cend%7Barray%7D%5Cright%5D)
= ![\left[\begin{array}{ccc}6+5&2+2\\9+20&3+8\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D6%2B5%262%2B2%5C%5C9%2B20%263%2B8%5C%5C%5Cend%7Barray%7D%5Cright%5D)
=
→ A