Answer:
Part 1) The length of the diagonal of the outside square is 9.9 units
Part 2) The length of the diagonal of the inside square is 7.1 units
Step-by-step explanation:
step 1
Find the length of the outside square
Let
x -----> the length of the outside square
c ----> the length of the inside square
we know that

step 2
Find the length of the inside square
Applying the Pythagoras Theorem

substitute



step 3
Find the length of the diagonal of the outside square
To find the diagonal Apply the Pythagoras Theorem
Let
D -----> the length of the diagonal of the outside square




step 4
Find the length of the diagonal of the inside square
To find the diagonal Apply the Pythagoras Theorem
Let
d -----> the length of the diagonal of the inside square




Answer:
yoo thanks u the goat
Step-by-step explanation:
Hello!
Let’s do it step-by-step, shall we? Don’t worry! These problems can be a bit tricky but you’ll get it in no time! It’s really simple.
So, we have (-7)(-5)
This means that the problem will be multiplied because of the parentheses. They substitute the multiplication sign.
So, we have -7 (multiplied by) -5= 35
So your answer would be 35. Hope this helps :) and good luck!
Answer:
6.75.
Step-by-step explanation:
Following PEMDAS, as there are no other variables, we move from right to left. 9 x 3 is 27, and 27 / 4 is 6.75.
Hope this helps!