Question

Write in standard form y=1/3(x+6)^2-9

Answer 1

Answer:

$y=\frac{1}{3}x^2+4x+3$

Step-by-step explanation:

we know that

The standard form of a quadratic equation is equal to

$ax^{2} +bx+c$

we have

$y=\frac{1}{3}(x+6)^2-9$

This is the equation of a vertical parabola written in vertex form

Expanded the quadratic equation

$y=\frac{1}{3}(x^2+12x+36)-9$

Apply distributive property right side

$y=\frac{1}{3}x^2+4x+12-9$

$y=\frac{1}{3}x^2+4x+3$ ---> quadratic equation in standard form