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Elina [12.6K]
3 years ago
7

I need help creating a real world problem

Mathematics
1 answer:
marshall27 [118]3 years ago
7 0
Jasmine goes to McDonalds to order food. A big mac costs $5 and large fries cost $3. If Jasmine was to buy one big mac with one batch of large fries, how much would she pay in total if a taxes of $10 was added on.

Answer: 5+3=8
8+10=18

The answer is $18 dollars.
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Which can't be lenght side of triangle
Luda [366]

Answer:

C. sides of 3, 4 and 7

can't form a triangle.

the longest side (7) must be shorter than the sum of the other 2 sides.

Step-by-step explanation:

5 0
3 years ago
Given f(x)=17x-18, find x when f(x)=33
vichka [17]
33=17x-18 add 18 both sides
51=17x. divide 17 both sides
3 = x
3 0
3 years ago
Is 4(y-30)=4y+12 how many solutions
Len [333]

Answer:

no solution exists

Step-by-step explanation:

5 0
3 years ago
What values of x satisfy the equation 2x^2 -3x +4 =0
BaLLatris [955]

Answer:

(3 ± √23 * i) /4

Step-by-step explanation:

To solve this, we can apply the Quadratic Equation.

In an equation of form ax²+bx+c = 0, we can solve for x by applying the Quadratic Equation, or x = (-b ± √(b²-4ac))/(2a)

Matching up values, a is what's multiplied by x², b is what's multiplied by x, and c is the constant, so a = 2, b = -3, and c = 4

Plugging these values into our equation, we get

x = (-b ± √(b²-4ac))/(2a)

x = (-(-3) ± √(3²-4(2)(4)))/(2(2))

= (3 ± √(9-32))/4

= (3 ± √(-23))/4

= (3 ± √23 * i) /4

6 0
3 years ago
Gourmet Pretzels bakes soft pretzels on an assembly line. It currently bakes 800 pretzels each eight-hour shift. If the producti
Delvig [45]

Answer:

Change in productivity will be 50%

So option (b) will be correct option

Step-by-step explanation:

It is given that it takes 8 hour to bake 800 pretzels

And there is a shift of 8 hours

So hourly production = \frac{800}{8} =100

Now the production is increases to 1200

Now hourly production = \frac{1200}{8}=150

So change in productivity  = \frac{150-100}{100}=50 %

So option (b) will be correct answer

6 0
4 years ago
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