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tatyana61 [14]
3 years ago
11

What is the probability of getting an even number of heads when flipping an unfair coin n times?

Mathematics
1 answer:
Xelga [282]3 years ago
5 0
The probility is 50 out of one hundred
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Please help me. ASAP.Please I need answer step-by-step.
nikitadnepr [17]

so this is how i was taught the inverse function.  f(x) is basicly the same thing as saying y

so y=x over x+3  

you switch the top x with y so it turns in to x=y over x+3

the problem should tell you what x equals so substitute x with the number it equals and then solve

here is an example f(x)=x over x+3 and x=14

x=y over x+3

14=y over 14+3

the inverse inverse function would probably be just solve the equation so just substitute the number they give you for x in for x

4 0
3 years ago
a baker is making bread dough.He uses 3 cups of flour for every 8 ounces of water. How many cups of flour will be use if he used
Nataliya [291]

Answer:

36 cups of flour

Step-by-step explanation:

if 3 cups of flour=8 ounces.what about 96 onces you cross multiply

7 0
3 years ago
Can y’all help me a question 25?!
Elenna [48]

Answer:

19.8839 miles away

Step-by-step explanation:

:)

3 0
2 years ago
MARSVECTORCALC6 3.4.020. My Notes A rectangular box with no top is to have a surface area of 64 m2. Find the dimensions (in m) t
ioda

Answer:

We would have

                                    l =w =\frac{8\sqrt{3}}{3} \\h = \frac{8\sqrt{3}}{6}

where " l " is  length, " w"  is width and "h" is height.

Step-by-step explanation:

Step 1

Remember that

         Surface area for a box with no top = lw+2lh+2wh = 64

where " l " is  length, " w"  is width and "h" is height.

 Step 2.

Remember as well that

                              Volume of the box = l*w*h

Step 3

 We can now use lagrange multipliers.  Lets say,

                                    F(l,w,h) = lwh

and

                                g(l,w,h) = lw+2lh+2wh = 64

By the lagrange multipliers method we know that                            

 

                                                     \nabla F  = \lambda \nabla g

Step 4

Remember that

                          \nabla F  = (wh,lh,lw)

and

                      \nabla g = (w+2h,l+2h , 2w+2l)

So basically you will have the system of equations

                              wh = \lambda (w+2h)\\lh = \lambda (l+2h)\\lw = \lambda (2w+2l)

Now, remember that you can multiply the first eqation, by "l" the second equation by "w" and the third one by "h" and you would get

                                   lwh = l\lambda (w+2h)\\\\lwh = w\lambda (l+2h)\\\\lwh = h\lambda (2w+2l)

Then you would get

                      l\lambda (w+2h) = w\lambda (l+2h) =  h\lambda (2w+2l)

You can get rid of \lambda from these equations and you would get

                         lw+2lh = lw+2wh =  2wh+2lh

And from those equations you would get

                                             l = w =2h

Now remember the original equation

                                    lw+2lh+2wh = 64

If we plug in what we just got, we would have

                                 l^{2} + l^{2} + l^2   =  64 \\3l^{2} = 64 \\l = w = \frac{8\sqrt{3} }{3} \\h = \frac{8\sqrt{3} }{6}

                       

                                                 

7 0
3 years ago
A circle is centered at (2, -5) and has radius 3. Write its equation in standard form. A) (x + 2)2 + (y - 5)2 = 3 B) (x - 2)2 +
ki77a [65]
D.
(x - h)^{2}  +  {(y - k)}^{2}  = r^{2}
Where (h, k) is the center of the circle and the radius is squared.
4 0
3 years ago
Read 2 more answers
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