-1/2=3/2k+3/2
Rewrite the equation to have k on left side
3/2k+3/2=-1/2
Simplify 3/2k
3k/2+3/2=12
Move all terms not containing k to right side
3k/2=1/2-3/2
3k/2=-2
Multiply both sifmdes by 2
2(3k/2)=-2(2)
3k=-4
Divide both sides by 3 to get k alone
3k/3=-4/3
K= -4/3
Answer:
The first four terms of the above sequence are 1, 6, 11, 16.
Step-by-step explanation:
A sequence is defined by the function f(n)=f(n-1)+5.
Where n represents the number of the term for n>1
First Put n = 2
f(2)=f(2-1)+5.
= f (1) + 5
= -4 + 5
= 1
Second Put n = 3
f(3)=f(3-1)+5.
= f (2) + 5
= 1 + 5
= 6
Third Put n = 4
f(4)=f(4-1)+5.
= f (3) + 5
= 6+ 5
= 11
Second Put n = 5
f(5)=f(5-1)+5.
= f (4) + 5
= 11 + 5
= 16
Therefore the first four terms of the above sequence are 1, 6, 11, 16.
Part A: 3x + 15 = 5x - 25
Part B: x = 20
12 / 6
Therefore the answer is 2
Hope this helped you today,
Have a good dayN
