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2 years ago

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a car salesman's total earnings , e , is a base salary pus a commission. the salesman has a base salary of $40,000 and receives

a commission of $200 for every car,c, he sells .what equation represents the total earnings for the salesman?

1 answer:

Orlov [11]2 years ago

4 0

40,000+ 200C= e

salary is a flat yearly pay, you don't get paid hourly.

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Carl has three lengths of cable, 5/6 yard long, 1/4 yard long, and 2/3 yard long. If he uses 1 yard of cable, how much cable is

Dafna1 [17]

He would have 9/12 yards left over because you have to create a common denominator which would be 12. so for 5/6 you would multiply by 2 so you have 10/12. 1/4 you have to multiply by 3 so you get 3/12. and 2/3 you have to multiply by 4 so you get 8/12. then you add them 10/12+3/12+8/12 = 21/12 which simplifies to 1 9/12 and because he used 1 yard he is left with 9/12.
final answer: 9/12 yards

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2 years ago

Virgil has 1/6 of a birthday cake left over. He wants to share the leftover cake with 3 friends. What fraction of the original c

klemol [59]

Answer:

Each of the 4 people will get 1/24 of the original cake

Step-by-step explanation:

The fractional part of cake left out is 1/6

This remaining cake is to be divided among four people.

Thus, each person will get

fractional part of cake left/total number of people

i.e 1/6/4

= 1/24

Each of the 4 people will get 1/24 of the original cake

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2 years ago

Graph y=4/7x−2 . Use the line tool and select two points on the line.

Lynna [10]

Answer:

Given equation of the line,

$y=\frac{4}{7}x-2$

If x = 0,

$y=\frac{4}{7}(0) - 2=0-2=-2$

Thus, the line intercepts y-axis at (0,-2)

If y = 0,

$0=\frac{4}{7}x-2\implies 2=\frac{4}{7}x\implies x=\frac{14}{4}=3.5$

Thus, the line intercepts x-axis at (3.5,0)

By joining these two points in the graph,

We will get the graph of the given line ( shown below )

4 0

3 years ago

K-1234=5678<br> what does k equal

artcher [175]

Answer:

k=6,912

Step-by-step explanation:

5678+1234=6912

5 0

2 years ago

Read 2 more answers

find the area of the trapezium whose parallel sides are 25 cm and 13 cm The Other sides of a Trapezium are 15 cm and 15 CM

Snezhnost [94]

$\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}$

Given - <u>A </u><u>trapezium</u><u> </u><u>ABCD </u><u>with </u><u>non </u><u>parallel </u><u>sides </u><u>of </u><u>measure </u><u>1</u><u>5</u><u> </u><u>cm </u><u>each </u><u>!</u><u> </u><u>along </u><u>,</u><u> </u><u>the </u><u>parallel </u><u>sides </u><u>are </u><u>of </u><u>measure </u><u>1</u><u>3</u><u> </u><u>cm </u><u>and </u><u>2</u><u>5</u><u> </u><u>cm</u>

To find - <u>Area </u><u>of </u><u>trapezium</u>

Refer the figure attached ~

In the given figure ,

AB = 25 cm

BC = AD = 15 cm

CD = 13 cm

<u>Construction</u><u> </u><u>-</u>

$draw \: CE \: \parallel \: AD \: \\ and \: CD \: \perp \: AE$

Now , we can clearly see that AECD is a parallelogram !

$\therefore$ AE = CD = 13 cm

Now ,

$AB = AE + BE \\\implies \: BE =AB - AE \\ \implies \: BE = 25 - 13 \\ \implies \: BE = 12 \: cm$

Now , In ∆ BCE ,

$semi \: perimeter \: (s) = \frac{15 + 15 + 12}{2} \\ \\ \implies \: s = \frac{42}{2} = 21 \: cm$

Now , by Heron's formula

$area \: of \: \triangle \: BCE = \sqrt{s(s - a)(s - b)(s - c)} \\ \implies \sqrt{21(21 - 15)(21 - 15)(21 - 12)} \\ \implies \: 21 \times 6 \times 6 \times 9 \\ \implies \: 12 \sqrt{21} \: cm {}^{2}$

Also ,

$area \: of \: \triangle \: = \frac{1}{2} \times base \times height \\ \\\implies 18 \sqrt{21} = \: \frac{1}{\cancel2} \times \cancel12 \times height \\ \\ \implies \: 18 \sqrt{21} = 6 \times height \\ \\ \implies \: height = \frac{\cancel{18} \sqrt{21} }{ \cancel 6} \\ \\ \implies \: height = 3 \sqrt{21} \: cm {}^{2}$

<u>Since </u><u>we've </u><u>obtained </u><u>the </u><u>height </u><u>now </u><u>,</u><u> </u><u>we </u><u>can </u><u>easily </u><u>find </u><u>out </u><u>the </u><u>area </u><u>of </u><u>trapezium </u><u>!</u>

$Area \: of \: trapezium = \frac{1}{2} \times(sum \: of \:parallel \: sides) \times height \\ \\ \implies \: \frac{1}{2} \times (25 + 13) \times 3 \sqrt{21} \\ \\ \implies \: \frac{1}{\cancel2} \times \cancel{38 }\times 3 \sqrt{21} \\ \\ \implies \: 19 \times 3 \sqrt{21} \: cm {}^{2} \\ \\ \implies \: 57 \sqrt{21} \: cm {}^{2}$

hope helpful :D

6 0

1 year ago