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ira [324]
3 years ago
13

the graph of f(x)=6(3)^x-1 from problem 2 moves closer and closer to the x-axis as x decreases. Does the graph ever reach the x-

axis?
Mathematics
1 answer:
I am Lyosha [343]3 years ago
4 0
No, the graph will never reach the x axis because it is an exponential equation, and y = 0 (the x axis) is an undefined asymptote.
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398.574986215 to the nearest ten-thousandth.
Julli [10]

Answer: 398.5750

Step-by-step explanation:

It is important to remember that the fourth digit after the decimal point is in the ten-thousandth place.

Then, given the  following number:

398.574986215

You can follow these steps in order ti round it to the nearest ten-thousandth:

1. You can identify that the digit in the ten-thousandth place is:

9

2. Identify the digit to the right of 9. This is:

8

3. Since:

 8>5

 You must round up. Increase the digit 9 by 1. (Notice that 9+1=10, then the digit to the left of  9 increases by 1 too). Then:

398.5750

3 0
3 years ago
What is the diameter?
Usimov [2.4K]

Answer:

13

Step-by-step explanation:

7 0
3 years ago
Consider the parent function f(x)=e^x and transformed function g(x)=-f(x)-4. Which features of function F function G are differe
eduard

There are no results for Consider the parent function f(x)=e^x and transformed function g(x)=-f(x)-4. Which features of function F function G are different

3 0
3 years ago
Let D = {-48, -14, -8, 0, 1, 3, 16, 23, 26, 32, 36} Determine which of the following statements are true and which are false. a)
morpeh [17]

Answer:

\forall x\in D if x is odd then x> 0 is true statement.

\forall x\in D if x is odd then x> 0 is true statement.

\forall x\in D if x is even then x≤0 is false statement.

\forall x\in D If the ones digit of x is 2, then the tens digit is 3 or 4 is true statement.

\forall x\in D if the ones digit of x is 6, then the tens digit is 1 or 2 is false statement.

Step-by-step explanation:

Consider the provided information.

D = {-48, -14, -8, 0, 1, 3, 16, 23, 26, 32, 36}

Part (A) \forall x\in D if x is odd then x> 0

Here only even numbers are less than 0 that means the statement is true.

\forall x\in D if x is odd then x> 0 is true statement.

Part (B) \forall x\in D if x is less than 0 then x is even.

Here only even numbers are less than 0 that means the statement is true.

\forall x\in D if x is odd then x> 0 is true statement.

Part (C) \forall x\in D if x is even then x≤0

Here we can see that 16, 26, 32, 36 are even number and also greater than 0. Thus the statement is false.

\forall x\in D if x is even then x≤0 is false statement.

Part (D) \forall x\in D If the ones digit of x is 2, then the tens digit is 3 or 4.

There is only one number whose ones digit is 2. i.e. 32 also the tens digit of the number 32 is 3. Which makes the above statement true.

\forall x\in D If the ones digit of x is 2, then the tens digit is 3 or 4 is true statement.

Part (E) \forall x\in D if the ones digit of x is 6, then the tens digit is 1 or 2.

Numbers having ones digit 6 are: 16, 26 and 36

Here, the tens digits are 1, 2 and 3 which is contradict to our statement. Hence the provided statement is false.

\forall x\in D if the ones digit of x is 6, then the tens digit is 1 or 2 is false statement.

8 0
3 years ago
Find the equation of the exponential function represented by the table below:
IgorC [24]

Answer:

y=2^{1-x}

Step-by-step explanation:

<u>Exponential Function</u>

When we need to express the exponential relation between two variables, we use the equation

y=Cr^{x}

where C, r are constants to be determined by using the given points from the table

For x=0, y=2, thus

2=C.r^{0}=C

We find that C=2

The equation is now

y=2r^{x}

Now we use the point x=1, y=1

1=2r

We find that

\displaystyle r=\frac{1}{2}

Thus, the equation is

\displaystyle y=2\left(\frac{1}{2}\right)^{x}

Rearranging

y=2(2)^{-x}=2^{1-x}

The required equation is

y=2^{1-x}

We can easily verify the last two points are also obtained by using the equation

7 0
3 years ago
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