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mihalych1998 [28]
3 years ago
5

What is the slope of a line parallel to the line y = - 7/5 x + 7?

Mathematics
1 answer:
Artist 52 [7]3 years ago
6 0

Answer:

The slope of a line parallel to that one would be -7/5

Step-by-step explanation:

Parallel lines have the same slope. The slope (in this form) is the coefficient of x. Therefore, it is -7/5 and a parallel line would have that same slope.

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Answer:

c. 0.1151

Step-by-step explanation:

d) the probability that, on average, fish are larger than 86 centimeters in length.The area under part of a normal probability curve is  directly proportional to probability and the value is calculated as

z = (x₁−x) /σ

where z = propability of normal curve

x₁ = variate mean = 86cm

x = mean of 80cm

σ = standard deviation = 5cm

applying the formula,

z= (86-80)/5

z = 6/5 =1.2

Using a table of partial areas beneath the standardized normal curve (see Table of normal curve, a z-value of 1.2 corresponds to an area of 0.3849 between the mean value. but, because the standard curve has 0.5, then will minus 0.3849 from 0.5= 0.5 - 0.3849 = 0.1151

Thus the probability of a fish are larger than 86 centimeters in length is 0.1151

5 0
3 years ago
A train travels 200 miles in 4 hours at a constant rate. What is the constant rate of change for the train in miles per hour? A.
Sav [38]

Answer:50 miles

Step-by-step explanation:

6 0
3 years ago
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Will mark brainliest, 60 points
il63 [147K]

Answer:

21 C

22 B

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Step-by-step explanation:

21 3m mean 3 times a certain number

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then 6^2 divided by 9+9= 13 i took the 9 from the 5^2 problem then divided it by 6^2

then 13 x 13 = 169

8 0
2 years ago
The area of a rectangle is 52 m2 , and the length of the rectangle is 5 m less than double the width. Find the dimensions of the
kotegsom [21]
52m^2= 2[(x-5)+(x)]. 52m^2= 2(2x-5). 52m^2=4x-10
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The city’s budget is $8,000,000. The city actually spends $12,000,000. What is the city’s deficit?
a_sh-v [17]

Answer:

four million

Step-by-step explanation:

just subtract 12 million by 8 million

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3 years ago
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