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7nadin3 [17]
3 years ago
12

For the diagram shown, which angles are corresponding angles ∠3 and ∠7 ∠8 and ∠6 ∠4 and ∠7 ∠3 and ∠5

Mathematics
1 answer:
natka813 [3]3 years ago
4 0

Answer:

< 3 and < 7

Step-by-step:

Corresponding angles mean that two angles are on the same side of the line. In this situation, the line is "t". Angles 3 and 7 are the only angles on the same side as each other.

Hope this helps!

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2y-8x=20 in slope intercept form
kupik [55]
The slope intercept formula: y=mx + b

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<span />
4 0
3 years ago
1. Find the area of the composite figure to the nearest hundredth.
Leto [7]

Answer:

#1: 751.56 mm²

#2: 477 km²

Step-by-step explanation:

First I noted the semicircle on the left, which has a radius of 12.5 mm. The formula for finding the area of a semicircle is 1/2(πr²).

1/2(3.14 * (12.5)²)

<em>12.5 squared is 156.25.</em>

1/2(3.14 * 156.25)

<em>Multiply 3.14 by 156.25 to get 490.625.</em>

1/2(490.625)

<em>Divide 490.625 by 2 to get 245.3125.</em>

245.3125 mm² for the semicircle

Then, I split the rest of into a 12.5 by 25 rectangle and a 31 by 12.5 triangle.

(12.5 * 25) + 1/2(31 * 12.5)

<em>Multiply 12.5 by 25 to get 312.5.</em>

312.5 + 1/2(31 * 12.5)

<em>Multiply 31 by 12.5 to get 387.5.</em>

312.5 + 1/2(387.5)

<em>Multiply 1/2 by 387.5 to get 193.75</em>

312.5 + 193.75

<em>Add 312.5 and 193.75 to get 506.25.</em>

506.25 mm² for the rest of the figure.

Now add the two measures, and you have your answer for #1.

245.3125 + 506.25 = 751.5625 mm², which rounds to 751.56 mm².

The area of the composite figure is 751.56 mm².

Now for #2. First, find the area of the triangle.

1/2(40 * 27)

<em>Multiply 40 by 27 to get 1080.</em>

1/2(1080)

<em>Multiply 1/2 by 1080.</em>

590 km² for the triangle.

Now find the area of the circle.

3.14 * 6²

3.14 * 36

113.04 km² for the circle.

Now subtract the area of the circle from the area of the triangle.

590 - 113.04

476.96 km², which rounds to 477.0 km².

The area of the shaded region is 477 km².

6 0
3 years ago
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Why is there always more than one parallelogram with the same area and base​
BaLLatris [955]

Answer:

If every line parallel to two lines intersects both regions in line segments of equal length, then the two regions have equal areas. In the case of your problem, every line parallel to the bases of the two parallelograms will intersect them in lines segments, each with a width of ℓ.

6 0
1 year ago
PLEASE HELP!!! WILL GIVE BRAINLIEST!!!
Tamiku [17]
It is a it is symmetric on both sides and it’s peak is at 3
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3 years ago
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