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2 years ago

Do I have this one right

Mathematics

2 answers:

Maslowich2 years ago

7 0

Yes that is right! Keep at it!

IceJOKER [234]2 years ago

3 0

Yeah,I'm sure you have it right. ;)

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Rate of 33.00 for 11 pounds of meat

gtnhenbr [62]

The answer is 3

hope this helps :)

4 0

2 years ago

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At time t, the position of a body moving along the s-axis is sequalsnegative t cubed plus 15 t squared minus 72 t m. a. Find t

larisa [96]

Answer:

Step-by-step explanation:

Given that at time t, the position of a body moving along the s-axis is sequalsnegative t cubed plus 15 t squared minus 72 t m

i.e. $s(t) = -t^3+15t^2-72 t$

Velocity is nothing but s'(t) = derivative of s

and acceleration is s"(t) = derivative of v(t)

$v(t) = -3t^2+30t-72\\=-3(t^2-10t+24)\\= -3(t-6)(t-4)$

a) v(t) =0 when t = 4 or 6

b) $a(t) = -6t+30$

a(t) =0 when t =5

c) Distance travelled by the body from 0 to 5 would be

$s(5)-s(0)\\= -5^3+15(5^2)-72(5)\\= -125+375-360\\=-110$

i.e. 110 miles (distance cannot be negative)

3 0

2 years ago

4 – (2y + 5) = 3(1 – 4y) show steps please

Lelu [443]

Answer/Step-by-step explanation:

Let's solve your equation step-by-step.

4−(2y+5)=3(1−4y)

Step 1: Simplify both sides of the equation.

4−(2y+5)=3(1−4y)

4+−1(2y+5)=3(1−4y)(Distribute the Negative Sign)

4+−1(2y)+(−1)(5)=3(1−4y)

4+−2y+−5=3(1−4y)

4+−2y+−5=(3)(1)+(3)(−4y)(Distribute)

4+−2y+−5=3+−12y

(−2y)+(4+−5)=−12y+3(Combine Like Terms)

−2y+−1=−12y+3

−2y−1=−12y+3

Step 2: Add 12y to both sides.

−2y−1+12y=−12y+3+12y

10y−1=3

Step 3: Add 1 to both sides.

10y−1+1=3+1

10y=4

Step 4: Divide both sides by 10.

10y

Answer:

y= 2/5

6 0

2 years ago

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What is 49% of $201.13

Nookie1986 [14]

Answer:

98.5537

Step-by-step explanation:

8 0

2 years ago

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In the diagram below,AB is the diameter of the circle with centre P.Point C lies on the y-axis.Given the coordinates of A and B

Step2247 [10]

Answer:

The coordinates of P are (-2,0)

The radius of the circle is 5.

Step-by-step explanation:

Analytic geometry

The diagram shows a circle with center P, and two points A(-6,3) and B(2,-3) that form the diameter of the circle.

The center of the circle lies at the midpoint of A and B. The midpoint (xm,ym) can be calculated by:

$\displaystyle x_m=\frac{x_1+x_2}{2}$

$\displaystyle y_m=\frac{y_1+y_2}{2}$

Substituting x1=-6, x2=2, y1=3, y2=-3:

$\displaystyle x_m=\frac{-6+2}{2}=\frac{-4}{2}=-2$

$\displaystyle y_m=\frac{3-3}{2}=0$

Thus, the coordinates of P are (-2,0)

b) The radius of the circle is the distance from the center to any point in its circumference. We can use the distance from P to A or B indistinctly.

Given two points A(x1,y1) and P(x2,y2), the distance between them is:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substituting x1=-6, x2=-2, y1=3, y2=0:

$r=\sqrt{(-2+6)^2+(0-3)^2}$

$r=\sqrt{4^2+(-3)^2}$

$r=\sqrt{16+9}=\sqrt{25}=5$

The radius of the circle is 5.

4 0

2 years ago