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irina [24]
2 years ago
12

Do I have this one right

Mathematics
2 answers:
Maslowich2 years ago
7 0
Yes that is right! Keep at it!
IceJOKER [234]2 years ago
3 0
Yeah,I'm sure you have it right. ;)
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Math question! <br> please help ASAP!
77julia77 [94]

Answer:

x = 14.04°

Step-by-step explanation:

Find x using the tangent ratio in the right triangle, that is

tan x = \frac{opposite}{adjacent} = \frac{5}{20} = \frac{1}{4}

Hence

x = tan^{-1}(0.25) = 14.04°

3 0
3 years ago
X^2y^8/x^7y^6 if x= -2 and y= 4
damaskus [11]

Answer:

- \frac{1}{2}

Step-by-step explanation:

Given

\frac{x^2y^8}{x^7y^6}

= \frac{y^{(8-6)} }{x^{(7-2)} }

= \frac{y^2}{x^5} , substitute values

= \frac{4^2}{(-2)^{5} }

= \frac{16}{-32}

= - \frac{1}{2}

7 0
3 years ago
2<br>What is the diameter of this circle if the circumference is 30 inches?​
ioda

Answer:

9.55 inches

Step-by-step explanation:

The diameter of a circle can be found by dividing the circumference by pi or 3.14. 30 divided by 3.14 is approximately 9.55.

8 0
3 years ago
En la ciudad la temperatura en la noche fue de 2 grados sobre cero y en la madrugada llegó a 12 grados bajo cero. ¿Qué diferenci
alexgriva [62]

Responder:

La temperatura bajó 12 °

Explicación paso a paso:

Dado que:

Temperatura en la noche = + 2 ° (2

Temperatura de la mañana = - 12 (12 ° bajo cero).

La diferencia de temperatura entre la noche y la madrugada:

Temperatura nocturna - temperatura por la mañana temprano

2 - (-12)

2 + 12 = 14

Hay una diferencia de temperatura de 12 °. La temperatura bajó 12 ° entre la noche y la madrugada.

8 0
2 years ago
(Ross 5.15) If X is a normal random variable with parameters µ " 10 and σ 2 " 36, compute (a) PpX ą 5q (b) Pp4 ă X ă 16q (c) PpX
pochemuha

Answer:

(a) 0.7967

(b) 0.6826

(c) 0.3707

(d) 0.9525

(e) 0.1587

Step-by-step explanation:

The random variable <em>X</em> follows a Normal distribution with mean <em>μ</em> = 10 and  variance <em>σ</em>² = 36.

(a)

Compute the value of P (X > 5) as follows:

P(X>5)=P(\frac{x-\mu}{\sigma}>\frac{5-10}{\sqrt{36}})\\=P(Z>-0.833)\\=P(Z

Thus, the value of P (X > 5) is 0.7967.

(b)

Compute the value of P (4 < X < 16) as follows:

P(4

Thus, the value of P (4 < X < 16) is 0.6826.

(c)

Compute the value of P (X < 8) as follows:

P(X

Thus, the value of P (X < 8) is 0.3707.

(d)

Compute the value of P (X < 20) as follows:

P(X

Thus, the value of P (X < 20) is 0.9525.

(e)

Compute the value of P (X > 16) as follows:

P(X>16)=P(\frac{x-\mu}{\sigma}>\frac{16-10}{\sqrt{36}})\\=P(Z>1)\\=1-P(Z

Thus, the value of P (X > 16) is 0.1587.

**Use a <em>z</em>-table for the probabilities.

8 0
3 years ago
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