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Nana76 [90]
2 years ago
5

Here is 93 points but answer this please If x = 4, what is the value of x3 + x - 5?

Mathematics
1 answer:
Luda [366]2 years ago
8 0

Answer:

11

Step-by-step explanation:

x3+x-5

3*4=12

12+4-5

16-5=11

pls i REALLY need brainliest

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A cube

Step-by-step explanation:

If you fold it, you'll see

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If an experimenter sets equal to .01, then she is defining a "statistically rare" event as an event occurring more than one time
Fynjy0 [20]

Answer:

The correct answer is an event occurring one or fewer times in 100 times if the null hypothesis is true.

Step-by-step explanation:

For a statistically rare event, its probability is relatively small and the event is very unlikely to occur.  Therefore, if an experimental sets equal to 0.01 which is statistically rare, then we can interpret this mathematically as:

p(event) = 0.01 = 1/100

where p(event) is the probability of the event.

In addition, statistically, null hypothesis signifies no major difference between the specified parameters, and any obvious difference that might occur as a result of experimental error. Thus, it can be concluded that the event is occurring one or fewer times in 100 times if the null hypothesis is true.

3 0
3 years ago
Which of the following statement must be true?I WILL MARK THE BRAINIEST
Anettt [7]

Answer:

d) XY > RS

Step-by-step explanation:

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5 0
2 years ago
Which powers have of value of 81.<br> Possible Answers: 1^81, 3^4, 6^4, 9^2, 27^3.
quester [9]

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4 0
2 years ago
Read 2 more answers
Given: △ACM, m∠C=90°, CP ⊥ AM
larisa86 [58]

Answer:  The answer is 3\dfrac{4}{7}.

Step-by-step explanation:  Given in the question that ΔAM is a right-angled triangle, where ∠C = 90°, CP ⊥ AM, AC : CM = 3 : 4 and MP - AP = 1. We are to find AM.

Let, AC = 3x and CM = 4x.

In the right-angled triangle ACM, we have

AM^2=AC^2+CM^2=(3x)^2+(4x)^2=9x^2+16x^2=25x^2\\\\\Rightarrow AM=5x.

Now,

AM=AP+PM=AP+(AP+1)\\\\\Rightarrow 2AP=AM-1\\\\\Rightarrow 2AP=5x-1.~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(A)

Now, since CP ⊥ AM, so ΔACP and ΔMCP are both right-angled triangles.

So,

CP^2=AC^2-AP^2=CM^2-MP^2\\\\\Rightarrow (3x)^2-AP^2=(4x)^2-(AP+1)^2\\\\\Rightarrow 9x^2-AP^2=16x^2-AP^2-2AP-1\\\\\Rightarrow 2AP=7x^2-1.~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(B)

Comparing equations (A) and (B), we have

5x-1=7x^2-1\\\\\Rightarrow 5x=7x^2\\\\\Rightarrow x=\dfrac{5}{7},~\textup{since }x\neq 0.

Thus,

AM=5\times\dfrac{5}{7}=\dfrac{25}{7}=3\dfrac{4}{7}.

8 0
3 years ago
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