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3 years ago

Nombra el conjunto de números reales.

Mathematics

2 answers:

Lorico [155]3 years ago

5 0

Answer:

Los números reales incluyen todos los números racionales, como el entero −5 y la fracción 4/3, y todos los números irracionales, como √2 (1.41421356 ..., la raíz cuadrada de 2, un número algebraico irracional).

Step-by-step explanation:

Fantom [35]3 years ago

4 0

Answer:

El conjunto de los números reales se forma al combinar el conjunto de números racionales y el conjunto de números irracionales. El conjunto de números reales consiste en todos los números que tienen un lugar en la recta numérica. Enteros …, -3, -2, -1, 0, 1, 2, 3, …

Step-by-step explanation:

corrígeme si esto está mal

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Read 2 more answers

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Vedmedyk [2.9K]

Answer:

$5.23\times 10^{-6}\ kg/mm^3=5230\ kg/m^3$

Step-by-step explanation:

Given : The density of a certain solid is $5.23\times 10^{-6}$ kg/mm³.

To find : Convert this density into kilograms per cubic meter ?

Solution :

We know that,

$1\ m^3=10^9\ mm^3$

or $10^9\ mm^3=1\ m^3$

So, $1 mm^3=\frac{1}{10^9}\ m^3$

$1 mm^3=10^{-9}\ m^3$

Converting $5.23\times 10^{-6}$ kg/mm³ into kg/m³,

$5.23\times 10^{-6}\ kg/mm^3=\frac{5.23\times 10^{-6}}{10^{-9}}\ kg/m^3$

$5.23\times 10^{-6}\ kg/mm^3=5.23\times 10^{-6+9}\ kg/m^3$

$5.23\times 10^{-6}\ kg/mm^3=5.23\times 10^{3}\ kg/m^3$

$5.23\times 10^{-6}\ kg/mm^3=5230\ kg/m^3$

Therefore, $5.23\times 10^{-6}\ kg/mm^3=5230\ kg/m^3$

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Answer:

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Step-by-step explanation:

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