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Virty [35]
3 years ago
5

Could something please help me with this, it's easy.

Mathematics
2 answers:
sergiy2304 [10]3 years ago
7 0

Answer:

C. 14 3/4

Step-by-step explanation:

I entered it into my graphing calculator.

Hunter-Best [27]3 years ago
4 0

Answer:

Step-by-step explanation:

4 7/12 + 2 3/4 + 7 5/12

Convert 2 3/4 to a common denominator

2 3/4 · 3/3 = 2 9/12

Then add

4 7/12 + 2 9/12 + 7 5/12 = 14 3/4 (c)

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Moxie wants to have $5000. how much money does she have to deposit in an account at 6% interest, compounded 3 times per year, in
BaLLatris [955]
<span>Moxie wants to have $5000. how much money does she have to deposit in an account at 6% interest, compounded 3 times per year, in order to have $5000 at the end of 6 years?  The formula for compound interest AMOUNT is

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4 0
4 years ago
The function below has at least one rational zero.
Dmitry_Shevchenko [17]

Answer:

x=-7,x=-1,x=-0.289898,x=0.689898

or x=-7,x=-1,x=\frac{1}{5}-\frac{\sqrt{6}}{5},x=\frac{1}{5}+\frac{\sqrt{6}}{5}

Step-by-step explanation:

<u>Factor by grouping</u>

g(x)=5x^4+38x^3+18x^2-22x-7\\\\g(x)=5x^4+33x^3-15x^2-7x+5x^3+33x^2-15x-7\\\\g(x)=x(5x^3+33x^2-15x-7)+1(5x^3+33x^2-15x-7)\\\\g(x)=(x+1)(5x^3+33x^2-15x-7)\\\\g(x)=(x+1)(5x^3+35x^2-2x^2-14x-x-7)\\\\g(x)=(x+1)(5x^2(x+7)-2x(x+7)-1(x+7))\\\\g(x)=(x+1)(x+7)(5x^2-2x-1)\\\\0=(x+1)(x+7)(5x^2-2x-1)\\

We can easily see that the first two zeroes are x=-1 and x=-7, however, the third zero will need the help of the quadratic formula:

0=5x^2-2x-1\\\\x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\ \\x=\frac{-(-2)\pm\sqrt{(-2)^2-4(5)(-1)}}{2(5)}\\\\x=\frac{2\pm\sqrt{4+20}}{10}\\ \\x=\frac{2\pm\sqrt{24}}{10}\\ \\x=\frac{2\pm2\sqrt{6}}{10}\\ \\x=\frac{2}{10}\pm\frac{2\sqrt{6}}{10}\\ \\x=\frac{1}{5}\pm\frac{\sqrt{6}}{5}\\\\x_1\approx0.689898\\\\x_2\approx-0.289898

Therefore, the zeroes of the function are x=-7,x=-1,x=-0.289898,x=0.689898

7 0
3 years ago
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