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stich3 [128]
2 years ago
6

A student wrote and simplified an expression for the perimeter of the rectangle. (Using the picture provided.)

Mathematics
1 answer:
muminat2 years ago
5 0

Answer:

I’m backk

Step-by-step explanation:

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Given that log 2 = 0.3010 and log 3 = 0.4771 , how can we find log 6 ? ​
bearhunter [10]

Answer:

\sf \log_{10}6=0.7781

Step-by-step explanation:

<u>Given</u>:

\sf \log_{10} 2 = 0.3010

\sf \log_{10} 3 = 0.4771

To find log₁₀ 6, first rewrite 6 as 3 · 2:

\sf \implies \log_{10}6=\log_{10}(3 \cdot 2)

\textsf{Apply the log product law}: \quad \log_axy=\log_ax + \log_ay

\implies \sf \log_{10}(3 \cdot 2)=\log_{10}3+\log_{10}2

Substituting the given values for log₁₀ 3 and log₁₀ 2:

\begin{aligned} \sf \implies \log_{10}3+\log_{10}2 & = \sf 0.4771+0.3010\\ & = \sf 0.7781 \end{aligned}

Therefore:

\sf \log_{10}6=0.7781

Learn more about logarithm laws here:

brainly.com/question/27953288

brainly.com/question/27963321

5 0
1 year ago
Read 2 more answers
a group of astronauts launched a model rocket from a platform. Its flight path is modeled by h= -4t^2+24t+13 where h is the heig
Eddi Din [679]

Answer:

6.5 seconds

Step-by-step explanation:

Keep in mind that when h=0, this is the same height for both when the model rocket takes off and lands, so when the rocket lands, time is positive. Thus:

h=-4t^2+24t+13\\\\0=-4t^2+24t+13\\\\t=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\ \\t=\frac{-24\pm\sqrt{24^2-4(-4)(13)}}{2(-4)}\\ \\t=\frac{-24\pm\sqrt{576+208}}{-8}\\\\t=\frac{-24\pm\sqrt{576+208}}{-8}\\\\t=\frac{-24\pm\sqrt{784}}{-8}\\\\t=\frac{-24\pm28}{-8}\\\\t=\frac{-24-28}{-8}\\ \\t=\frac{-52}{-8}\\ \\t=\frac{52}{8}\\\\t=6.5

So, the amount of seconds that the model rocket stayed above the ground since it left the platform is 6.5 seconds

5 0
2 years ago
Read 2 more answers
Which choice is equivalent to the expression below? HELP PLEASE THE PROBLEM IS ON THE PICTURE!!!!!!!
zvonat [6]
The correct answer is C
5 0
3 years ago
Can someone help me with this? I’ll mark you brainliest
nirvana33 [79]

Answer:

sorry man can't help you with this one

8 0
2 years ago
Use the discriminant to describe the roots of each equation. Then select the best description. x2 - 5x + 7 = 0
miv72 [106K]
The general form of a quadratic (second degree) equation is 

a x^{2} +bx+c=0, where

D= b^{2}-4ac is called the Discriminant.


The Discriminant determines how many roots the equation will have as follows:

i)  if D>0, the equation has 2 roots.
ii) if D=0, the equation has 1 double root.
iii) if D<0, the equation has no roots.


In our equation, x^{2} -5x+7=0, a=1, b=-5, c=7

so the discriminant is D=(-5)^2-4*1*7=25-28<0


Thus the equation has no roots.


Remark: the equation has no roots in the Real numbers, but it has 2 roots in a larger set of numbers to be discussed in the future, the Complex numbers.
5 0
3 years ago
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