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3 years ago

I need some help please! ^_^

1 answer:

7 0

Perpendicular lines will have negative reciprocal slopes. What that means is if u have a slope of 1/2, to find the negative reciprocal, flip the slope and change the sign.......flip 2/1, change the sign -2/1 or just -2. So the negative reciprocal for the slope of 1/2 is -2.

A. y = 1/5x + 3.....slope here is 1/5, so for a perpendicular line, u r gonna need an equation with the slope of -5.....and that would be : y + 3 = -5(x + 2).

B. Parallel lines will have the same slope. y = 5x - 2...the slope here is 5...so a parallel line will have a slope of 5.

y = mx + b
slope(m) = 5
(8,-2)...x = 8 and y = -2
now we sub, we r looking for b, the y intercept
-2 = 5(8) + b
-2 = 40 + b
-2 - 40 = b
-42 = b

so ur parallel equation is : y = 5x -42

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Answer:

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Step-by-step explanation:

Area = length * width

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3 years ago

1. Which point on the axis satisfies the inequality y

grigory [225]

Answer:

1) Point $(1,0)$ -----> see the attached figure N $1$

2) The value of x is $4$

3) I quadrant

4) $(1,1)$

5) $y>-5x+3$

Step-by-step explanation:

Part 1)

we know that

If the point satisfy the inequality

then

the point must be included in the shaded area

The point $(1,0)$ is included in the shaded area

Part 2)

we have

$x-2y\geq 4$

see the attached figure N $2$

we know that

The value for x on the boundary line and the x axis is equal to the x-intercept of the line $x-2y= 4$

For $y=0$

Find the value of x

$x-2(0)= 4$

$x=4$

The solution is $x=4$

Part 3)

we have

$x\geq 0$ -----> inequality A

The solution of the inequality A is in the first and fourth quadrant

$y\geq 0$ -----> inequality B

The solution of the inequality B is in the first and second quadrant

the solution of the inequality A and the inequality B is the first quadrant

Part 4) Which ordered pair is a solution of the inequality?

we have

$y\geq 4x-5$

we know that

If a ordered pair is a solution of the inequality

then

the ordered pair must be satisfy the inequality

we're going to verify all the cases

case A) point $(3,4)$

Substitute the value of x and y in the inequality

$x=3,y=4$

$4\geq 4(3)-5$

$4\geq 7$ ------> is not true

therefore

the point $(3,4)$ is not a solution of the inequality

case B) point $(2,1)$

Substitute the value of x and y in the inequality

$x=2,y=1$

$1\geq 4(2)-5$

$1\geq 3$ ------> is not true

therefore

the point $(2,1)$ is not a solution of the inequality

case C) point $(3,0)$

Substitute the value of x and y in the inequality

$x=3,y=0$

$0\geq 4(3)-5$

$0\geq 7$ ------> is not true

therefore

the point $(3,0)$ is not a solution of the inequality

case D) point $(1,1)$

Substitute the value of x and y in the inequality

$x=1,y=1$

$1\geq 4(1)-5$

$1\geq -1$ ------> is true

therefore

the point $(1,1)$ is a solution of the inequality

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we know that

The equation of the line has a negative slope

The y-intercept is the point $(3,0)$

The x-intercept is a positive number

The solution is the shaded area above the dashed line

the equation of the line is $y=-5x+3$

The inequality is $y>-5x+3$

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