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solong [7]
3 years ago
10

Help plz:))) I’ll mark you BRAINLIEST

Mathematics
1 answer:
serg [7]3 years ago
5 0

Answer:

I think the answer is C

Step-by-step explanation:

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How many times larger is the 5 in 528, 394 as in 352, 107?
seraphim [82]

Answer: B 10 Times large

Step-by-step explanation:The first 5 is 500,000 And the second 5 is 50,000

500,000÷ 50,000= 10

7 0
2 years ago
What is the answer of X2/3??
Yuri [45]
1/3x^2

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7 0
3 years ago
How do i factor this?
Jet001 [13]
You need to watch a video on polynomials, that's how i learned to factor Polynomials

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3 0
3 years ago
Assume lim f(x)-6 and lim g(x)-9. Compute the following limit and state the limit laws used to justify the computation.
emmasim [6.3K]

Answer:

4

Step-by-step explanation:

<h3><u>some relevant limit laws</u></h3>

lim C = C where c is a constant.

lim( f(x)  + g(x)) =lim f(x) + lim g(x)

lim( f(x)g(x)) =lim f(x) * lim g(x)

lim( cg(x)) =clim g(x)

lim( f(x)/g(x)) =lim f(x) / lim g(x) if  lim g(x) is not equal to zero.

lim( f(x))^2 = (lim f(x) )^2

lim  square root( f(x)) = square root(lim f(x) )

\lim_{n \to 3} g(x)  = 9\\\\\lim_{n \to 3} f(x)  = 6\\\\ \lim_{n \to 3} \sqrt[3]{f(x)g(x) + 10} \\\\ = \lim_{n \to 3} \sqrt[3]{f(x)g(x) + 10}\\\\= \sqrt[3]{lim_{n \to 3}f(x) \times lim_{n \to 3}g(x) + 10}\\\\= \sqrt[3]{6 \times 9 + 10}\\\\= \sqrt[3]{64}

= 4

4 0
3 years ago
I need help from 1 to 13 please!
valina [46]
1. 11 between x and 0 between y 
2. 0 between x and 12 between y 
3. 3 between x and 0 between y 
4. 0 between x and 11 between y 
5. 0 between x and 6 between y 
6. (4,-2) and (-6,-2) 
7. (2,12) and (2,-4) 
8. (-7,-2) and (-7,-8) 
9. (4,5) and (4,-7) 
10. (9,9) and (-11,9) 
11. (4,2) and (-10,2) 
12. 4 units 
13. 7 units 
Hope this helps!
8 0
3 years ago
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