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mel-nik [20]
3 years ago
11

Simplify 4 times the 4th root of 128.

Mathematics
2 answers:
gizmo_the_mogwai [7]3 years ago
7 0

4\sqrt[4]{128}


We can simplify the 128 under the fourth root sign. Since 2^4 is 16, and 128 is divisible by 16, we can pull that out of the radical.


4\sqrt[4]{128} = 4\sqrt[4]{16*8} = 4\sqrt[4]{2^4 * 8} = 4*2\sqrt[4]{8}  = 8\sqrt[4]{8}

finlep [7]3 years ago
6 0

Answer:

8 times the 4th root of 8

Step-by-step explanation:

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Step-by-step explanation:

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Hope this helps! :)

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Why is 1/2 not useful as a benchmark to compare 5/8 and 9/10?
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1/2 would not be a useful benchmark to compare these 2 fractions because both of them are greater than half. The benchmark fraction 1/2 is most useful when one fraction is less than half and the other more than 1/2. 5/8 is more than 4/8(1/2), and 9/10 is more than 5/10(1/2).
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Step-by-step explanation:

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4 years ago
Find the median, Q1, Q3, interquartile range (IQR), and list any outliers. 2) 74, 63, 69, 62, 33, 79, 70, 60, 107, 119
e-lub [12.9K]

Answer:

Since the sample size is n=10 we can find the first quartile taking in count the first 5 observations from the data set ordered and we have this:

33  60  62  63  69

Q_1 =62

We can find the third quartile taking in count the last 5 observations from the data set ordered and we have this:

70  74  79 107 119

Q_3 =79

And finally the median can be calculated with the average of the two moddlie values and we got:

Median= \frac{69+70}{2} =69.5

And the IQr would be:

IQR = 79-62= 17

Step-by-step explanation:

Assuming that 2 is not part of the data we have:

74, 63, 69, 62, 33, 79, 70, 60, 107, 119

We can sort the values on increasing order and we got:

33  60  62  63  69  70  74  79 107 119

Since the sample size is n=10 we can find the first quartile taking in count the first 5 observations from the data set ordered and we have this:

33  60  62  63  69

Q_1 =62

We can find the third quartile taking in count the last 5 observations from the data set ordered and we have this:

70  74  79 107 119

Q_3 =79

And finally the median can be calculated with the average of the two moddlie values and we got:

Median= \frac{69+70}{2} =69.5

And the IQr would be:

IQR = 79-62= 17

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4 years ago
What's the answer to all my questions?
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