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Nikolay [14]
3 years ago
8

Why is 1/2 not useful as a benchmark to compare 5/8 and 9/10?

Mathematics
2 answers:
pentagon [3]3 years ago
4 0
1/2 would not be a useful benchmark to compare these 2 fractions because both of them are greater than half. The benchmark fraction 1/2 is most useful when one fraction is less than half and the other more than 1/2. 5/8 is more than 4/8(1/2), and 9/10 is more than 5/10(1/2).
SVEN [57.7K]3 years ago
4 0

Solution:

1/2 is not a useful benchmark to compare 5/8 and 9/10 because if we observe closely we found that

\frac{1}{2}\times \frac{1}{2}\times \frac{1}{2}\times \frac{1}{2} =\frac{1}{8}

and

\frac{1}{2}\times \frac{1}{2}\times \frac{1}{2}\times \frac{1}{2}\times\frac{1}{2}=\frac{1}{10}

In the first case 1/2 comes four times and in the second case 1/2 comes 5 times in multiplication so logically the second number 9/10 should be smaller than the first number 5/8.

But 9 is greater than 5 it mean second number should be greater than the first number.

Both the above two conclusions are contradictory to each other.

Hence we can not use 1/2 as a benchmark to compare 5/8 and 9/10.

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Your answer is D that helped
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The Slow Fix auto shop charges $28 for parts and $48 per hour of labor. The We Work Cheaper auto shop charges $59 for parts and
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Answer: 10 hours

Step-by-step explanation:

Given

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When these costs are the same

28+48x=59+44.90x\\3.1x=31\\x=10\ hours

6 0
3 years ago
You have a six-sided die that you roll once. Let Ri denote the event that the roll is i. Let G j denote the event that the roll
Misha Larkins [42]

Answer:

a. P (R3 | G1)=\frac{1}{5}

b. P (R6| G3)= \frac{1}{3}

c. P(G3|E)=\frac{2}{3}

d. P (E|G3)=\frac{2}{3}

Step-by-step explanation:

The sample space associated with the random experiment of throwing a dice is is the equiprobable space {R1, R2, R3, R4, R5, R6}. Then,

a. The conditional probability that 3 is rolled given that the roll is greater than 1? P (R3 | G1) = \frac{P (R3\bigcap G1)}{P(G1)} = \frac{1/6}{5/6} = \frac{1}{5}

b. What is the conditional probability that 6 is rolled given that the roll is greater than 3? P (R6| G3) = \frac{P (R6\bigcap G3)}{P(G3)} = \frac{1/6}{3/6} = \frac{1}{3}

c. What is P [GIE], the conditional probability that the roll is greater than 3 given that the roll is even? P(G3|E) = \frac{P (G3\bigcap E)}{P(E)} = \frac{2/6}{3/6} = \frac{2}{3}

d. Given that the roll is greater than 3, what is the conditional probability that the roll is even? P (E|G3) = \frac{P (E\bigcap G3)}{P(G3)} = \frac{2/6}{3/6} = \frac{2}{3}

6 0
3 years ago
Which equation represents a hyperbola with a center at (0,0), a vertex at (0,60), and a focus at (0,-65)
Leona [35]
Given that the hyperbola has a center at (0,0), and its vertices and foci are on y-axis. This, the equation of the hyperbola is of the form
x²/a²-y²/b²=-1 (a>0, b>0)
In the equation, vertices are (0, +/-b) .
Thus, 
b=60
Foci (0,+/-√(a²+b²))
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a²=625
a²=25²
hence the equation is:
x²/25²-y²/60²=-1
7 0
3 years ago
Read 2 more answers
I’m confused on this and i just moved from schools so
Elina [12.6K]

Answer:

(-2,3)

Step-by-step explanation:

The point where two lines cross should be your answer!!!

(-2,3) is where the two lines meet/cross!!

That is the definition of a system on a graph!

-Where two lines meet/cross!!

6 0
2 years ago
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