9. ¹/₃(x + 6) = 8
¹/₃(x) + ¹/₃(6) = 8
¹/₃x + 2 = 8
<u> - 2 - 2</u>
3 · ¹/₃x = 6 · 3
x = 18
15. ¹/₅(x + 10) = 6
¹/₅(x) + ¹/₅(10) = 6
¹/₅x + 2 = 6
<u> - 2 - 2</u>
5 · ¹/₅x = 4 · 5
x = 20
20. ¹/₈(24x + 32) = 10
¹/₈(24x) + ¹/₈(32) = 10
3x + 4 = 10
<u> - 4 - 4</u>
<u>3x</u> = <u>6</u>
3 3
x = 2
32. 5 - ¹/₂(x - 6) = 4
5 - ¹/₂(x) - ¹/₂(-6) = 4
5 - ¹/₂x + 3 = 4
5 + 3 - ¹/₂x = 4
8 - ¹/₂x = 4
<u>- 8 - 8</u>
-2 · (-¹/₂x) = -4 · (-2)
x = 8
33. ²/₃(3x - 6) = 3
²/₃(3x) - ²/₃(6) = 3
2x - 4 = 3
<u> + 4 + 4</u>
<u>2x</u> = <u>7</u>
2 2
x = 3¹/₂
Answer: 38.555
Step-by-step explanation:
Although the number of new wildflowers is decreasing, the total number of flowers is increasing every year (assuming flowers aren't dying or otherwise being removed). Every year, 25% of the number of new flowers from the previous year are added.
The sigma notation would be:
∑ (from n=1 to ∞) 4800 * (1/4)ⁿ , where n is the year.
Remember that this notation should give us the sum of all new flowers from year 1 to infinite, and the values of new flowers for each year should match those given in the table for years 1, 2, and 3
This means the total number of flowers equals:
Year 1: 4800 * 1/4 = 1200 ]
+
Year 2: 4800 * (1/4)² = 300
+
Year 3: 4800 * (1/4)³ = 75
+
Year 4: 4800 * (1/4)⁴ = 18.75 = ~19 (we can't have a part of a flower)
+
Year 5: 4800 * (1/4)⁵ = 4.68 = ~ 5
+
Year 6: 4800 * (1/4)⁶ = 1.17 = ~1
And so on. As you can see, it in the years that follow the number of flowers added approaches zero. Thus, we can approximate the infinite sum of new flowers using just Years 1-6:
1200 + 300 + 75 + 19 + 5 + 1 = 1,600
The radius is 6
Complete the square on the equation and get
(x-6)^2 + (y-6)^2 =36
The circle equation is
(x-h)^2 + (y-k)^2 = r^2
Center(h,k) r=radius
The answer is C. 21/50 is 0.42. 7/50 is 0.14. 19/50 is 0.38. 43/50 is 0.86. To convert a fraction to a decimal, you will have to divide the numerator by the denominator.
Hope this helped.
