Answer: The following three equations could be used to determine the rate:
x*(time there) = 3 miles
(x+1)*(time back) = 3 miles
(time there) + (time back) = 2.5 hr
Step by step (including the actual solution x):
Equation for the trip there:
x*(time there) = 3 miles
Equation for the trip back:
(x+1)*(time back) = 3 miles
And we also know that:
(time there) + (time back) = 2.5 hr
So we have three equations with three unknowns and can solve for x. Let us call
(time there): t1
(time back): t2
The solution (I skipped the gory details of solving, but you can verify by plugging the values back into the equations) is
Rate x = 2 miles/hour
(time there) = 1.5 hours
(time back) = 1 hour
Hello :
the general term is : an = a1×r^(n-1)
a1 : the first term....( a1 = 6)
r : the common ratio......( r = -1/3 )
when : n = 8 a8 is the eighth term : a8 = 6×(-1/3)^7
a8 =- 6×(1/3)^7 because : (-1/3)^7 = - (1/3)^7
a8 = -2 ×(3/3^7)
a8 = -2×(1/3^6)
a8 = (-2)/[ 3^6 ]
Answer:
60+61+62= 183
Step-by-step explanation:
x + x-+1 + x+2 = 183
3x +3 = 180
3x =180
x=60
Answer:
Al estudiante le falta caminar 
de kilómetro.
Step-by-step explanation:
Un estudiante debe recorrer dos tercios de kilómetro para llegar al colegio. Dos tercios equivale a la fracción 
.
El estudiante avanza medio kilómetro en bus. Un medio equivale a la fracción 
, por lo tanto un medio es la mitad de una cantidad. Para calcular la distancia recorrida en bus se realiza la siguiente multiplicación:
Resolviendo:
Entonces, la distancia recorrida en bus es de kilómetro.
Para calcular la distancia recorrida a pie se calcula la diferencia entre la distancia total a recorrer por el estudiante y la distancia recorrida en bus. Esto es:
Resolviendo:
<u><em>Al estudiante le falta caminar </em></u><u><em> de kilómetro.</em></u>
Try to multiply if its not there then divide.
