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Brut [27]
3 years ago
10

What is the value of x in this problem? 2/4=x/15

Mathematics
2 answers:
irina [24]3 years ago
8 0
2/4 = x/15
*cross multiply*
2(15) = 4(x)
30 = 4x
7.5 = x

Hope this helps!
rodikova [14]3 years ago
5 0
The answer should be X=7
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Jennifer took a long multiple choice, end of year vocabulary test. The ratio of numbers of problems Jennifer got correct to the
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Jennifer got 30% on her test!

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3 years ago
S part of a statistic project, a math class weighed all the children who were willing to participate as shown below.
katovenus [111]

Answer:

18 children weighed less than 50 pounds.

Step-by-step explanation:

Ok, adding into the explanation what the heck this kind of a table is. The "stem" column is the tens place of each of the children's weights. The "leaf" is the ones digit of each of the children's weights. So in the row where the stem is 2, there were 2 kids weighing 23 and 25 pounds.

For your question, we have to add up how many students have a weight with a "stem" less than 5, because that's where 50 pounds starts.

8 + 2 + 5 + 3 = 18 children weighed less than 50 pounds.

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3 years ago
Lucy reads 72 chapters of a book in 8 hours. What is her rate in chapters per hour?
Sophie [7]
She read nine chapters each hour
8 0
3 years ago
Read 2 more answers
Use the cosine ratio or the inverse cosine to solve for x. Round your answer to the nearest tenth.
maria [59]

Answer:

x ≈ 12.6 m

Step-by-step explanation:

By using cosine ratio in the given right triangle RTS,

cos(S)° = \frac{\text{Adjacent side}}{\text{Hypotenuse}}

cos(33)° = \frac{\text{ST}}{\text{SR}}

cos(33)° = \frac{x}{15}

x = 15.cos(33)°

x = 12.58

x ≈ 12.6 m

Therefore, measure of side ST = 12.6 m is the answer.

7 0
3 years ago
A sample of 38 observations is selected from one population with a population standard deviation of 3.4. The sample mean is 100.
kaheart [24]

Answer:

a. two-tailed test

b. reject H0 if Z>1.96 or Z<-1.96

c. Z = 1.73

d. we have failed to reject the null hypothesis

e. P-value = 0.0418

Step-by-step explanation:

We will use a Z test to resolve this, an it will be a two-tailed test because the hypothesis statements are not indicating a specific direction for the significant difference (H0 : μ1 = μ2 ; H1 : μ1 ≠ μ2), this also means that the significanclevel will be divided between the both tails (2.5% en each tail for the rejection regions). See attached drawing for reference.

We need to find our critical value:

Zα/2 = Z(0.05/2) = 0.025

If we look for 0.025 in a Z table we will find that the critical value is 1.96 to the right, and by symmetry -1.96 to the left. So our decision rule will be to reject H0 if Z>1.96 or Z<-1.96

The Z test will be done using the next equation:

Z = (x⁻1 - x⁻2) - (μ1 - μ2) / √( σ²1/n1 + σ²2/n2

Because we are testing the null hypothesis we know that μ1 - μ2 must be zero if they are supposed to be equal (H0 : μ1 = μ2), so we calculate as follows:

Z = (100.5 - 98.8) - (0) / √( (3.4)²/38 + (5.8)²/51 = 1.7/0.9817 = 1.73

Z<1.96, therefore we have failed to reject the null hypothesis

The P-value for this test would be represented by the probability of Z being greater than 1.73, so we can look for it in any Z table, finding that its value is 0.0418, and because P-value>0.025 we again confirm that we don't have evidence statistically significant to reject the null hypothesis

4 0
3 years ago
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