Which graph represents the solution set of the inequality Negative 9 greater-than x?

Please help me with this homework

fenix001 [56]

A dollar and 92 cents

3 0

2 years ago

-2x + y = 6 -2x + y = -1 Plz help with this problem Elimination

vladimir1956 [14]

The answer is no solution

Step-by-step explanation:

The equation is $-2x+y=6$ and $-2x+y=-1$

Subtracting these two equations, we get,

$-2x+y=6\\-2x+y=-1\\-------\\0=7$

Thus, $0=7$ is not possible.

Hence, the system of equations have no solutions.

5 0

3 years ago

Help plz what is 7-6v=-5-8v

kirill115 [55]

v=-6 is the right answer. First you had to subtract by 7 from both sides of equation, and it gave us, $7-6v-7=-5-8v-7$ . And then simplify, and it gave us, $-6v=-8v-12$ . You can also add by 8v from both sides of equation, and it gave us, $-6v+8v=-8v-12+8v$ . Next simplify, and it gave us, $2v=-12$ . Then you divide by 2 from both sides of equation, and it gave us, $\frac{2v}{2}=\frac{-12}{2}$ . And finally simplify, and it gave us the answer is v=-6 is the right answer. Hope this helps! And thank you for posting your question at here on brainly, and have a great day. -Charlie

3 0

3 years ago

WILL GIVE BRAINLIEST!!!! :)

just olya [345]

WRW , RWR, The Only Ones I Could Think Of

8 0

3 years ago

Read 2 more answers

A psychologist is interested in knowing whether adults who were bullied as children differ from the general population in terms

MissTica

Answer:

$t = \frac{39.5-30.6}{\frac{6.6}{\sqrt{25}}}= 6.74$

The degrees of freedom are given by:

$df =n-1= 25-1=24$

Now we can calculate the p value with the following probability:

$p_v = 2*P(t_{24}>6.74)= 5.69x10^{-7}$

And for this case since the p value is lower compared to the significance level $\alpha=0.05$ we can reject the null hypothesis and we can conclude that the true mean for this case is different from 30.6 at the significance level of 0.05

Step-by-step explanation:

For this case we have the following info given:

$\bar X = 39.5$ represent the sample mean

$s =6.6$ represent the sample deviation

$\mu = 30.6$ represent the reference value to test.

$n = 25$ represent the sample size selected

The statistic for this case is given by:

$t =\frac{\bar X -\mu}{\frac{s}{\sqrt{n}}}$

And replacing we got:

$t = \frac{39.5-30.6}{\frac{6.6}{\sqrt{25}}}= 6.74$

The degrees of freedom are given by:

$df =n-1= 25-1=24$

Now we can calculate the p value with the following probability:

$p_v = 2*P(t_{24}>6.74)= 5.69x10^{-7}$

And for this case since the p value is lower compared to the significance level $\alpha=0.05$ we can reject the null hypothesis and we can conclude that the true mean for this case is different from 30.6 at the significance level of 0.05

3 0

3 years ago