I don’t really get this question so if anyone knows it please help

Mathematics

1 answer:

Mars2501 [29]3 years ago

3 0

Answer:

$116.82\:\text{square inches}$

Step-by-step explanation:

The window consists of a large square and 4 smaller triangles on the outside. The side length of this square is marked as 10, and therefore the area of this square is $10^2=100\:\mathrm{in^2}$ .

The area of a triangle is given by $\frac{1}{2}\cdot b\cdot h$ . Since the problem states that the overlapping squares are congruent, both legs of the triangle will be $2.9$ and intersect at a $90^{\circ}$ angle.

Thus, the sum of all four triangles is $\frac{1}{2}\cdot 2.9\cdot 2.9\cdot 4=16.82\:\mathrm{in^2}$ .

Therefore, the area of the window is:

$100+16.82=\boxed{116.82\:\mathrm{in^2}}$

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A rectangular box has length x and width 3. The volume of the box is given by y = 3x(8 – x). The greatest x-intercept of the gra

CaHeK987 [17]

Consider rectangular box with

length x units (x≥0);
width 3 units;
height (8-x) units (8-x≥0, then x≤8).

The volume of the rectangular box can be calculated as

$V_{box}=\text{length}\cdot \text{width}\cdot \text{height}.$

In your case,

$V_{box}=3\cdot x\cdot (8-x).$

Note that maximal possible value of the height can be 8 units (when x=0 - minimal possible length) and the minimal possible height can be 0 units (when x=8 - maximal possible length).

From the attached graph you can see that the greatest x-intercept is x=8, then the height will be minimal and lenght will be maximal.

Then the volume will be V=0 (minimal).

Answer: correct choices are B (the maximum possible length), C (the minimum possible height)