The answer is B(11, 2sqrt(12) )
proof

the main equation of the circle is (x-x1)²+(y-y1)²=R²
where C(x1, y1) is the center
so if the center is the origin, it is O(0,0), and the equation becomes
<span> (x)²+(y)²=R²
</span>and the circle passes through the point (-5,2) so we can write
(-5)²+12²=R², it implies R= sqrt(25+144)=sqrt(169)=13

and for <span>B(11, 2sqrt(12) ) </span>11²+ (2sqrt(12))²= 121 + 48= 169= 13
it is checked.

3 0

3 years ago

Jane needs 6 1/2 of fabric to make a dress. She has one piece of fabric that is 1 1/2 yards and another piece of fabric that is

telo118 [61]

Answer:

1 1/2

Step-by-step explanation:

1 1/2 + 3 1/2 = 5

6 1/2 - 5 =1 1/2

4 0

3 years ago

Calculate the future value of $51,123.21, earning interest at a rate of that is compounded daily for 20 years and 2 months (use

mina [271]

The compound interest formula is : $A = P(1+ \frac{r}{n})^n ^t$

where, A= Future value including the interest,

P= Principle amount, r= rate of interest in decimal form,

t= number of years and n= number of compounding in a year

Here, in this problem P= $ 51,123.21 , t= 20 years and 2 months

So, t= 20 + (2/12) years

t= 20 + 0.17 = 20.17 years

As the amount is compounded daily, so n= (12×30)= 360 [Using the traditional Banker’s rule of 30 days per month]

Thus, $A = 51,123.21( 1+ \frac{r}{360})^3^6^0^*^2^0^.^1^7$

$A= 51,123.21 (1+\frac{r}{360})^7^2^6^1^.^2$

When the interest rate is given, then we can use this equation for finding the future value.

3 0

3 years ago

100 Brainliest up for grabs to person who can answer all of these with no links:

kogti [31]

Using a discrete probability distribution, it is found that:

a) There is a 0.3 = 30% probability that he will mow exactly 2 lawns on a randomly selected day.

b) There is a 0.8 = 80% probability that he will mow at least 1 lawn on a randomly selected day.

c) The expected value is of 1.3 lawns mowed on a randomly selected day.

<h3>What is the discrete probability distribution?</h3>

Researching the problem on the internet, it is found that the distribution for the number of lawns mowed on a randomly selected dayis given by:

P(X = 0) = 0.2.

P(X = 1) = 0.4.

P(X = 2) = 0.3.

P(X = 3) = 0.1.

Item a:

P(X = 2) = 0.3, hence, there is a 0.3 = 30% probability that he will mow exactly 2 lawns on a randomly selected day.

Item b:

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.2 = 0.8$

There is a 0.8 = 80% probability that he will mow at least 1 lawn on a randomly selected day.

Item c:

The expected value of a discrete distribution is given by the <u>sum of each value multiplied by it's respective probability</u>, hence:

E(X) = 0(0.2) + 1(0.4) + 2(0.3) + 3(0.1) = 1.3.

The expected value is of 1.3 lawns mowed on a randomly selected day.

More can be learned about discrete probability distributions at brainly.com/question/24855677

6 0

3 years ago