All categories

3 years ago

Find the product -a2 b2 c2 (a+b-c)

1 answer:

7 0

Use the distributive property:
$a(c+b)=ab+ac$
And
$a^n\cdot a^m=a^{n+m}\\\\a=a^1$

$-a^2b^2c^2(a+b-c)=-a^2ab^2c^2-a^2b^2bc^2+a^2b^2c^2c=-a^3b^2c^2-a^2b^3c^2+a^2b^2c^3$

You might be interested in

A sequence is defined by the recursive formula f (n + 1) = f(n) – 2. If f(1) = 18, what is f(5)?

anyanavicka [17]

For this case we have the following recursive formula:
$f (n + 1) = f (n) - 2
$
What we must do in this case is to evaluate different values of n until we find f (5)
We have then:
For n = 1:
$f (1 + 1) = f (1) - 2

f (2) = f (1) - 2

f (2) = 18 - 2

f (2) = 16$
For n = 2:
$f (2 + 1) = f (2) - 2

f (3) = f (2) - 2

f (3) = 16 - 2

f (3) = 14$
For n = 3:
$f (3 + 1) = f (3) - 2

f (4) = f (3) - 2

f (4) = 14 - 2

f (4) = 12$
For n = 4:
$f (4 + 1) = f (4) - 2

f (5) = f (4) - 2

f (5) = 12 - 2

f (5) = 10$
Answer:
The value of the recursive formula for f (5) is given by:
$f (5) = 10$

6 0

3 years ago

Read 2 more answers

How do you solve -9( -4r + 6s ) + 3s - 7(6s - 2r)

slavikrds [6]

Answer: 2.1 Pull out like factors :

6s - 2r = -2 • (r - 3s)

Equation at the end of step

((0-(9•(6s-4r)))+3s)--14•(r-3s)

Pulling out like terms

4.1 Pull out like factors : 6s - 4r = -2 • (2r - 3s)

Equation at the end of step

((0--18•(2r-3s))+3s)--14•(r-3s)

Final result :

7 0

3 years ago

Justin started a lawn service business. His rate to maintain an average size lawn is $35. It costs Justin $750 to start the busi

Ronch [10]

Answer:

Step-by-step explanation:

Cost function: Fixed costs+ Variable costs

In this case Justin will have to pay $750 to star the business, this is his fixed cost. And then, he will have to pay $1,50 per each lawn, this is his variable cost because it depends on the number of lawns he sells.

C(x)= $750+$1,50x

Revenue function (R(x)):

R(x)= Price * Number of units sold (x)

R(x)= $35*x

Profit function ((P(x))= Revenue function (R(x))-Cost function (C(x))

P(x)= $35x- [$750+$1,50x]

P(x)= $33,5-$750

4 0

3 years ago

Solve 1/3a2-1/a=1/6a2

nlexa [21]

Solve for a over the real numbers:
a^2/3 - 1/a = a^2/6

Bring a^2/3 - 1/a together using the common denominator 3 a:
(a^3 - 3)/(3 a) = a^2/6

Cross multiply:
6 (a^3 - 3) = 3 a^3

Expand out terms of the left hand side:
6 a^3 - 18 = 3 a^3

Subtract 3 a^3 - 18 from both sides:
3 a^3 = 18

Divide both sides by 3:
a^3 = 6

Take cube roots of both sides:
Answer: a = 6^(1/3)

8 0

4 years ago

Read 2 more answers

What is the lcm of 9, 45, and 81

Free_Kalibri [48]

9 LCM=3x3=9, 45 LCM=5x9=45, 81 LCM=9x9=81

5 0

3 years ago