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3 years ago

Is 0.243 greater than 0.88

Mathematics

2 answers:

love history [14]3 years ago

5 0

No it is not greater than 0.88

disa [49]3 years ago

3 0

.234 is greater than 0.88 because if you add 0 into 0.88, its 0.880. In decimal form, the lower the decimal is the greater value worth.

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If p and q are non-zero rational numbers, and s and t are irrational numbers, select all of the statements that are always false

Svetllana [295]

Answer:

The false choices are A, C, and E

Step-by-step explanation:

Let's make an example:

p=1

q=2

s=sqrt(3)

t=sqrt(6)

Since pq=1*2=2, the answer is rational and A is false.

Since pt=1*sqrt(6)=sqrt(6), the answer is irrational and B is true.

Since p/q=1/2=0.5, the answer is rational and C is false.

Since st=sqrt(3)*sqrt(6)=sqrt(18), the answer is irrational and D is true.

Since s/t=sqrt(3)/sqrt(6)=sqrt(1/2), the answer is irrational and E is false.

4 0

3 years ago

Cassie's broker charges her a commission of $4.25 for every ten shares of stock bought or sold. Cassie buys 92 shares of Hyren A

olya-2409 [2.1K]

Answer:

2,850

Step-by-step explanation:

4.25 x 9 = 38.25

4.25 x 13 = 55.25

4.25 x 12 = 51

13.70 x 92 = 1260.4

3.28 x 130 = 426.4

8.06 x 126 = 1015.56

all totals would equal 2,846.86, which to the nearest would be $2,850

4 0

3 years ago

Solve t/he system of linear equations given by x + y = 1 and ax − by = c, where a, b, c are real numbers. Note: The solution in

Phantasy [73]

Answer:

see explanation

Step-by-step explanation:

Given the 2 equations

x + y = 1 → (1)

ax - by = c → (2)

In (1) subtract y from both sides

x = 1 - y → (3)

Substitute x = 1 - y into (2)

a(1 - y) - by = c ← distribute left side

a - ay - by = c ( subtract a from both sides )

- ay - by = c - a ( multiply through by - 1 )

ay + by = a - c ← factor out y from each term on the left side

y(a + b) = a - c ← divide both sides by (a + b)

y = $\frac{a-c}{a+b}$ ← substitute into (3)

x = 1 - $\frac{a-c}{a+b}$ = $\frac{a+b}{a+b}$ - $\frac{a-c}{a+b}$ = $\frac{a+b-a+c}{a+b}$ = $\frac{b+c}{a+b}$

8 0

3 years ago

Can u help? this is due in an hour

Marysya12 [62]

Answer:

4 pairs of earrings

Step-by-step explanation:

3.75 e + 9.50 < 25

3.75 e < 25 - 9.50 = 15.50

e < 15.50 ÷ 3.75 ≈ 4.13

e = 4 pairs of earrings

3 0

3 years ago

A manufacturer of Christmas light bulbs knows that 10% of these bulbs are defective. It is known that light bulbs are defective

Inessa05 [86]

Answer:

(a) P(X $\leq$ 20) = 0.9319

(b) Expected number of defective light bulbs = 15

Step-by-step explanation:

We are given that a manufacturer of Christmas light bulbs knows that 10% of these bulbs are defective. It is known that light bulbs are defective independently. A box of 150 bulbs is selected at random.

Firstly, the above situation can be represented through binomial distribution, i.e.;

$P(X=r) = \binom{n}{r} p^{r} (1-p)^{2} ;x=0,1,2,3,....$

where, n = number of samples taken = 150

r = number of success

p = probability of success which in our question is % of bulbs that

are defective, i.e. 10%

Now, we can't calculate the required probability using binomial distribution because here n is very large(n > 30), so we will convert this distribution into normal distribution using continuity correction.

So, Let X = No. of defective bulbs in a box

Mean of X, $\mu$ = $n \times p$ = $150 \times 0.10$ = 15

Standard deviation of X, $\sigma$ = $\sqrt{np(1-p)}$ = $\sqrt{150 \times 0.10 \times (1-0.10)}$ = 3.7

So, X ~ N( $\mu = 15, \sigma^{2} = 3.7^{2})$

Now, the z score probability distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

(a) Probability that this box will contain at most 20 defective light bulbs is given by = P(X $\leq$ 20) = P(X < 20.5) ---- using continuity correction

P(X < 20.5) = P( $\frac{X-\mu}{\sigma}$ < $\frac{20.5-15}{3.7}$ ) = P(Z < 1.49) = 0.9319

(b) Expected number of defective light bulbs found in such boxes, on average is given by = E(X) = $n \times p$ = $150 \times 0.10$ = 15.

5 0

3 years ago