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svetoff [14.1K]
3 years ago
10

Is 0.243 greater than 0.88

Mathematics
2 answers:
love history [14]3 years ago
5 0
No it is not greater than 0.88

disa [49]3 years ago
3 0
.234 is greater than 0.88 because if you add 0 into 0.88, its 0.880. In decimal form, the lower the decimal is the greater value worth.
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Find the value of x .... need help ASAP
dangina [55]

We know: The sum of the angles of each quadrilateral is 360°.

Therefore we have equation:

x + 3x + 4x + 2x = 360

10x = 360     |:10

x = 36

7 0
3 years ago
Can you change this into y=x format so I can graph it easier please, thankyou. I'll give you brainliest.
Natali [406]
Y=-3x+1 this is the answer I think
7 0
4 years ago
What is the answer to this?
amm1812

Answer:

<h2>40.1 cm</h2>

solution,

BC=8.4 cm

AB=12 cm

BD=4.1 cm

We have to find out: AC ,CD

using Pythagoras theorem:

In ∆ABC ,<B=90°

{(ac)}^{2}  =  {(ab)}^{2}  +  {(bc)}^{2} \\  {(ac)}^{2}   =  {(12)}^{2}  +  {(8.4)}^{2}  \\  {(ac)}^{2}  = 144 + 70.56 \\  {(ac)}^{2}  = 214.56 \\ ac =  \sqrt{214.56}  \\ ac = 14.64 \: cm

Similarly,

In ∆BCD, CB=90

cd =   \sqrt{ {(8.4)}^{2} +  {(4.1)}^{2}  }

=  \sqrt{70.56 + 16.81}  \\  =  \sqrt{87.37}  \\  = 9.34 \: cm

Perimeter:

AC+CD+AD

=14.64+9.34+(12+4.1)

=40.08

= 40.1 cm

Hope this helps...

Good luck on your assignment..

7 0
3 years ago
Phytagoras therom solving method​
Anna [14]

Answer:

{hyp}^{2}  =  {adj}^{2}  +  {opp}^{2}

this is the formula u can use it on any Pythagoras theorm problem

8 0
3 years ago
A new airport is in its planning phase. One particular challenge is that there are several tall buildings in the vicinity. In pa
mixer [17]

Answer:

<em>Could an airplane take off and clear this tall building?  YES</em>

Step-by-step explanation:

<u>Trigonometry</u>

The building and the ground form a right (90°) angle. The path of the airplane (assumed a straight line) completes the right triangle.

The takeoff angle of the plane θ=15° has the height of the building (450 feet) as the opposite side and the horizontal distance from the end of the runway (2500 feet) as the adjacent side.

The tangent of θ is defined as the following ratio:

\displaystyle \tan\theta=\frac{\text{opposite leg}}{\text{adjacent leg}}

\displaystyle \tan \theta=\frac{450}{2500}

\displaystyle \tan \theta=0.18

Calculating the inverse tangent function:

\theta=\arctan 0.18

\theta\approx 10^\circ

This means the angle needed to clear the tall building is about 10° and it's within the maximum airplane's takeoff angle.

Could an airplane take off and clear this tall building?  YES

8 0
3 years ago
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