I think it is A as $16,845,562,487,550/ 3.11591917 x 10^8 is <span>54062.89948 so the nearest answer is A
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Answer:
1. x = 15, y = 8
2. m∠MSN = 90°
3. x = 20
4. y = 9
5. x = 8, m∠PQS = 24, m∠SQR = 66
6. y = 15, m∠RPT = 55, m∠TPW = 35
Step-by-step explanation:
1. to solve for y
9y + 18 = 90
9y + 18 - 18 = 90 - 18
9y = 72
9y/9 = 72/9
y = 8
to solve for x
5x + x = 90
6x = 90
6x/6 = 90/6
x = 15
2. m∠MSN = 90°, because ∠MSN is a right angle, which is equal to 90
3. To find x
3x + 10 + x = 90
3x + x = 4x
4x + 10 = 90
4x + 10 - 10 = 90 - 10
4x = 80
4x/4 = 80/4
x = 20
4. To find y
7y - 3 + 3y + 3 = 90
7y + 3y = 10
-3 + 3 = 0
10y = 90
10y/10 = 90/10
y = 9
5. To find x
3x + 8x + 2 = 90
3x + 8x = 11x
11x + 2 = 90
11x + 2 - 2 = 90 -2
11x = 88
11x/11 = 88/11
x = 8
To find ∠PQS
∠PQS = 3x
x = 8
so 3(x) = 3(8)
3(8) = 24
so ∠PQS = 24
To find ∠SQR
∠SQR = 8x + 2
x = 8
so ∠SQR = 8(x) + 2 = 8(8) + 2
8(8) + 2
= 64 + 2
= 66
6. To find y
4y - 5 + 2y + 5 = 90
4y + 2y = 6y
-5 + 5 = 0
6y = 90
6y/6 = 90/6
y = 15
To find ∠RPT
∠RPT = 4y - 5
y = 15
so ∠RPT = 4y - 5 = 4(15) - 5
4(15) - 5
= 60 - 5
= 55
To find ∠TPW
∠TPW = 2y + 5
y = 15
so ∠TPW = 2y + 5 = 2(15) + 5
2(15) + 5
= 30 + 5
= 35
Answer:
Step-by-step explanation:
Given
On first day bag contained 1 kernels
on second bag contained 2 kernels of corn
on third day bag contained 4 kernels of corn
on n th day bag contains 
kernels of corn
thus on 26 th day bag contains 
kernel
Each kernel weigh 0.07 gm
Therefore kernels weighs 
Therefore on 26 th day kernel weighs 23,488.1024 kg
Ill take a guess of... idk. the second or the third one.
