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KatRina [158]
3 years ago
5

A right triangle has:

Mathematics
1 answer:
Tom [10]3 years ago
7 0

Answer:

An isosceles right triangle has 2 congruent sides.

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I am the fewest number of coins needed to
Aleksandr [31]

Answer:

6 coins

Step-by-step explanation:

3 dimes

1 nickel

2 pennies

8 0
3 years ago
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I need help with creating some equations for an assignment. These are the types of equations I need:
kondor19780726 [428]
Hi there!

Here are some examples for you:

Two one step equations:
6x = 36
y + 5 = 10

Two equations containing fractions:
1/2x = 4
3/4y + 1 = 8

One equation using the distributive property:
2(x + 5) = 3

One equation with a decimal:
2.5x + 5 = 10

One real world problem that is solved by an equation:
At the beginning, I had 5 cups of flour. I made a batch of cookies. Now, I have 3.5 cups of flour. How much flour did I use?
5 - x = 3.5

Hope this helps!! :)
If there's anything else that I can help you with, please let me know!
7 0
3 years ago
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What is the sum of two numbers that do not have a common factor?
damaskus [11]
Are you looking for the the term
4 0
3 years ago
What number fall between the square root of 180
zvonat [6]
It will fall betwenn the square root of 169 which is 13 and 196 is 14
7 0
3 years ago
In a G.P the 3rd term is 4 times the 1st term and the sum of the 2nd term and the 4th term is 30.find the common ratio,find the
STALIN [3.7K]

Answer:

the common ratio is either 2 or -2.

the sum of the first 7 terms is then either 765 or 255

Step-by-step explanation:

a geometric sequence or series of progression (these are the most common names for the same thing) means that every new term of the sequence is created by multiplying the previous term by a constant factor which is called the common ratio.

so,

a1

a2 = a1×f

a3 = a2×f = a1×f²

a4 = a3×f = a1×f³

the problem description here tells us

a3 = 4×a1

and from above we know a3 = a1×f².

so, f² = 4

and therefore the common ratio = f = 2 or -2 (we need to keep that in mind).

again, the problem description tells us

a2 + a4 = 30

a1×f + a1×f³ = 30

for f = 2

a1×2 + a1×2³ = 30

2a1 + 8a1 = 30

10a1 = 30

a1 = 3

for f = -2

a1×-2 + a1×(-2)³ = 30

-10a1 = 30

a1 = -3

the sum of the first n terms of a geometric sequence is

sn = a1×(1 - f^(n+1))/(1-f) for f <>1

so, for f = 2

s7 = 3×(1 - 2⁸)/(1-2) = 3×-255/-1 = 3×255 = 765

for f = -2

s7 = -3×(1 - (-2)⁸)/(1 - -2) = -3×(1-256)/3 = -3×-255/3 =

= -1×-255 = 255

4 0
2 years ago
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