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KatRina [158]
3 years ago
5

A right triangle has:

Mathematics
1 answer:
Tom [10]3 years ago
7 0

Answer:

An isosceles right triangle has 2 congruent sides.

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Help help pls help quick pls help help
uysha [10]
Answer: I’m pretty sure its D) 1 1/9
5 0
3 years ago
Read 2 more answers
I don’t understand??
Rina8888 [55]

Answer:

understand it lol

Step-by-step explanation:

4 0
3 years ago
PLEASE HELP ME I WILL GIVE YOU POINTS
Brilliant_brown [7]

Answer:I got 18.28

Step-by-step explanation:

so for getting the perimeter, you only need the outer line, so you sum the measurements you have for the rectangle: 1+2+2+7= 12. After that you need the circumference of the circle, you can figure it out by using the formula C = 2pi(r) You can find the radius by substracting the known sides of the rectangle attached to the circle from the bottom base and then dividing it in 2, leaving us with a radius of 2. Then we input values; C=2pi(2) which equals 4pi, but we need to divide that in half since it’s only half a circle. That leaves us with 2pi, or 6.28. Then we add the perimeter of the square, which was 12, and 6.28+12= 18.28

4 0
2 years ago
A cube with an edge of length has a volume of 64 units. What is the length of ? Hint: Volume of a cube is LxWxH.
aleksandr82 [10.1K]

Answer:

it is 4

Step-by-step explanation:

5 0
3 years ago
What are the coordinates of the endpoints of the midsegment for △DEF that is parallel to DE¯¯¯¯¯?
Readme [11.4K]

Answer:

The endpoints of the midsegment for △DEF that is parallel to DE, are (-1,3.5) and (-1,2).

Step-by-step explanation:

If a line connecting the midpoint of two sides and parallel to the third side of the triangle, then it is called a midsegment.

From the given figure it is noticed that the vertices of the triangle are D(1,4), E(1,1) and F(-3,3).

If the midsegment is parallel to DE, then the end points of the midsegment are mid point of DF and EF.

Midpoint formula.

Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

Midpoint of DF,

Midpoint=(\frac{1-3}{2},\frac{4+3}{2})

Midpoint=(-1,3.5)

Midpoint of EF,

Midpoint=(\frac{1-3}{2},\frac{1+3}{2})

Midpoint=(-1,2)

Therefore the endpoints of the midsegment for △DEF that is parallel to DE, are (-1,3.5) and (-1,2).

3 0
3 years ago
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