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NemiM [27]
3 years ago
8

Lines j and k are parallel how to solve

Mathematics
1 answer:
Ede4ka [16]3 years ago
7 0
I can't answer your question without a picture... Sorry.
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Which is equivalent to 2 5/6<br><br>A. 5/3<br>B. 7/6<br>C. 17/6<br>D. 12/5
Dimas [21]
The answer would be C (17/6)
This is because;
6 goes into 17 twice leaving a reminder of 5.
8 0
2 years ago
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Please help. Trig: Laws of Cosines
Nonamiya [84]

Answer:

11.4

Step-by-step explanation:

d² = 6² + 6² - 2(6)(6)cos145

d² = 130.9789472

d = 11.44460341

3 0
3 years ago
7-18 use part 1 of the fundamental theorem of calculus to find the derivative of the function.
blondinia [14]

\displaystyle h(x)=\int\limits_{1}^{\sqrt{x}}~\cfrac{z^2}{z^4+1}dz~\hspace{10em}\cfrac{dh}{du}\cdot \stackrel{chain~rule}{\cfrac{du}{dx}\implies \cfrac{dh}{dx}} \\\\[-0.35em] ~\dotfill\\\\ u=\sqrt{x}\implies \cfrac{du}{dx}=\cfrac{1}{2\sqrt{x}} \\\\[-0.35em] ~\dotfill

\cfrac{dh}{dx}\implies \displaystyle \cfrac{d}{du}\left[ \int\limits_{1}^{u}~\cfrac{z^2}{z^4+1}dz \right]\cdot \cfrac{1}{2\sqrt{x}}\implies \left[ \cfrac{u^2}{u^4+1} \right]\cdot \cfrac{1}{2\sqrt{x}} \\\\\\ \stackrel{substituting~back}{\left[ \cfrac{(\sqrt{x})^2}{(\sqrt{x})^4+1} \right]\cdot \cfrac{1}{2\sqrt{x}}}\implies \cfrac{x}{x^2+1}\cdot \cfrac{1}{2\sqrt{x}}\implies \cfrac{\sqrt{x}}{2x^2+2}

7 0
1 year ago
-7x - 2y = 19<br> 4x + y = -12<br> Solve the system
nalin [4]

-7x - 2y = 19

4x + y = -12

Set y equal to each other (opposite signs are fine and you could also set x equal instead of y)

-7x - 2y = 19

8x + 2y = -76

Add equations together

x = -52

Plug x value into an equation

4(-52) + y = -12

Solve for y

-208 + y = -12

y = 196

Hope this helps! ;)

4 0
3 years ago
Sis Avila (STUDEN...
vesna_86 [32]

Answer:

sorry I dont know the way u put it makes no sense

3 0
3 years ago
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