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igor_vitrenko [27]
3 years ago
14

Find the product AB if possible A = (1 -6 1 -8 -1 -9 -4 -1 -9) B = (-4 -5 1 -3 3 -4 -1 4 9)

Mathematics
1 answer:
allsm [11]3 years ago
8 0
A=-92 and B=-241 so if we multiply -92 and -242 we get 7712. So answer is 7712.
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There are 96 female staff in an office. If the ratio of male staff to female staff is 3:4, find the number of male staff​.
Alex

Answer:60 male staff

Step-by-step explanation:

Ok, there are 96 female staff. The ratio of male to female is 3:4. We’re going to use a proportion which looks like this. 3/4 = x/96. X is a variable that takes the place of the male staff since we don’t know what it is. Now, the question is what do we do to get from 4 to 96. So 96/4 = 24, so 4 x 20 = 96. To keep this ratio equivalent whatever you do to the top you have to do to the bottom so 4 x 20 = 96 and 3 x 20 = 60. So there are 60 male staff.

4 0
3 years ago
Someone help me lol..
disa [49]

Answer:

1/3x + 3 is the correct answer, hope it help

6 0
3 years ago
A scientist has a sample of bacteria that initially contains 10 million microbes. They observe the sample and finds that the num
sergiy2304 [10]

Answer:

M(t) = 6.7 * 10⁷ (67 million)

Minutes (t) =55

Step-by-step explanation:

1. Write an exponential equation that represents M, the total number of bacterial microbes in millions, as a function of t, the number of minutes the sample has been observed.

For answering this question, we will use the following formula:

M(t) = B₀ * g ^(t/m), where:

•M(t) represents the total number of bacterial microbes in millions.

• B₀ represents the initial population of bacteria in millions.

• g represents the growth factor.

• t represents the total number of minutes we will observe the bacteria growing.

• m represents the time in minutes it takes to the growth factor g to occur.

2. Then, determine how much time, to the nearest minute, will pass until there are 67 million bacterial microbes.

M(t) = B₀ * g ^(t/m)

Replacing with the values we know:

6.7 * 10⁷ = 10⁷ * 2 ^(t/20)

6.7 = 2 ^(t/20) (Dividing by 10⁷ at both sides)

ln 6.7 = ln 2 ^(t/20)

ln 6.7 = t/20 ln 2

ln 6.7/ ln 2 = t/20

t = ln 6.7/ln 2 * 20

t = 2.74 * 20

t = 54.88

t ≅ 55 (rounding to the nearest minute)

3 0
2 years ago
Hey guys ! Can anyone help me with these problems please and thanks
AnnyKZ [126]

1)

m = 3√2√2

= 6

n = a

= 3√2

<u>Answer = </u><u> </u><u>D</u><u>)</u><u> </u><u>m</u><u> </u><u>=</u><u> </u><u>6</u><u> </u><u>,</u><u> </u><u>n</u><u> </u><u>=</u><u> </u><u>3</u><u>√</u><u>2</u>

2)

m = n = a

m = 3

n = 3

<u>A</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u><u> </u><u>=</u><u> </u><u>A</u>

3 0
2 years ago
6x+4y=2 10x-8y=32 what is the exact solution by using elimination
Alexeev081 [22]
First, let's multiply the first equation by two. This is because we have to eliminate either x or y by subtraction or addition so that means either both of the x's or both of the y's in the two equations have to be equal. Thus multiplying the first equation by 2 will give 12x+8y=4.
Next, subtract equation two from equation one:
We get a third equation, 2x-0= -28
Thus, x=-28/2. x= -14
In the same way, to find y, we need to eliminate the x's in both equations. This can be done by multiplying the first equation by 5 and the second by 3
Thus : 30x+20y=10 and 30x-24y=96
Subtracting the second equation from the first, we have 0+44y=-86
y=-86/44
y = 1.96 or 43/22
6 0
3 years ago
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