Answer:
A. a quadratic function can only have one y-intercep
By using pythagoras theorem where
(Base)^2 +(perpedicular)^2 = (hypotenuse)^2
So,
(5)^2 +(12)^2 = (hypotenuse)^2
25 + 144 = (hypotenuse)^2
169 = (hypotenuse)^2
13 = hypotenuse
So, hypotenuse = 13
Answer:
midpoint m= <u>(</u><u>x1 </u><u>+</u><u>x2</u> , <u>y1 </u><u>+</u><u> </u><u>y2</u><u>)</u>
2. 2
Step-by-step explanation:
M =(<u>0</u><u>+</u><u>2</u><u>. </u>, <u>0</u><u>+</u><u>2</u><u>)</u>
2. 2
M=(1,1)
Answer:
a=8
Step-by-step explanation:
Since this is a right triangle, we can use the Pythagorean theorem
a^2 +b^2 = c^2 where a and b are the legs and c is the hypotenuse
a^2 +15^2 = 17^2
a^2 +225 = 289
Subtract 225 from each side
a^2 +225-225=289-225
a^2 = 64
Take the square root of each side
sqrt(a^2) = sqrt(64)
a = 8
I can give you a link https://youtu.be/aUy-_WnEV30 . I hope this answers your problem, and gives you greater insight. Sorry I couldn't do more :(
