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alukav5142 [94]
3 years ago
10

Brooklynn mows the lawn every other weekend, She can mow 12,000 square feet in 2/3 hour. The lawn is 36,000 square feet. How lon

g does it take her to mow the entire lawn?
Mathematics
2 answers:
quester [9]3 years ago
8 0

Answer:

2/3 hour = 40 mins

36000 / 12000= 3

3x40= 120mins

Total 2 Hours

Step-by-step explanation:

geniusboy [140]3 years ago
4 0

Answer:2 hours

Step-by-step explanation:

3x12,000=36,000

2x3=6divided by 3=2

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Answer:

Step-by-step explanation:

-4=2x+16

-16. -16

-20=2x

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5 0
3 years ago
Alison knits 1/10 of scarf in 4/5 of an hour. what fraction of a scarf can alison knit in 1 hour? and how do u solve it?
pav-90 [236]
For this case we can make the following rule of three:
 1/10 scarf ------> 4/5 hour
 x ------------------> 1 hour
 Clearing the value of x we have:
 x = (1 / (4/5)) * (1/10)
 Rewriting we have:
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 Answer:
 
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8 0
3 years ago
Read 2 more answers
Pls, look at the picture for the question.
lyudmila [28]

Answer:

Positive gradient and the gradient is 3/2x

4 0
2 years ago
The force of gravity on Mars is different than on Earth. The function of the same situation on Mars would be represented by the
sweet-ann [11.9K]

Answer:

If thrown up with the same speed, the ball will go highest in Mars, and also it would take the ball longest to reach the maximum and as well to return to the ground.

Step-by-step explanation:

Keep in mind that the gravity on Mars; surface is less (about just 38%) of the acceleration of gravity on Earth's surface. Then when we use the kinematic formulas:

v=v_0+a\,*\,t\\y-y_0=v_0\,* t + \frac{1}{2} a\,\,t^2

the acceleration (which by the way is a negative number since acts opposite the initial velocity and displacement when we throw an object up on either planet.

Therefore, throwing the ball straight up makes the time for when the object stops going up and starts coming down (at the maximum height the object gets) the following:

v=v_0+a\,*\,t\\0=v_0-g\,*\,t\\t=\frac{v_0}{t}

When we use this to replace the 't" in the displacement formula, we et:

y-y_0=v_0\,* t + \frac{1}{2} a\,\,t^2\\y-y_0=v_0\,(\frac{v_0}{g} )-\frac{g}{2} \,(\frac{v_0}{g} )^2\\y-y_0=\frac{1}{2} \frac{v_0^2}{g}

This tells us that the smaller the value of "g", the highest the ball will go (g is in the denominator so a small value makes the quotient larger)

And we can also answer the question about time, since given the same initial velocity v_0 , the smaller the value of "g", the larger the value for the time to reach the maximum, and similarly to reach the ground when coming back down, since the acceleration is smaller (will take longer in Mars to cover the same distance)

3 0
3 years ago
Please help it’s urgent! it’s tangent lines
sleet_krkn [62]
The answer should be 24, because you can mark out 5,and 10 cuz it doesn’t make since
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