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eimsori [14]
2 years ago
9

Find a possible value of b. 5x2 - bx - 8​

Mathematics
1 answer:
pychu [463]2 years ago
3 0

Answer:

Step-by-step explanation:

Without more input from you, it's hard to find an exact value for b.  However, b may take on a large range of values.  b = 10 and b = -3 (chosen arbitrarily) are acceptable choices.

Take a look at the quadratic formula.  The discriminant is b^2 - 4ac.  There is nothing about this equation that restricts or forbids the use of any value of b.

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3 years ago
Help me find the arc length of this. Thank you.
BabaBlast [244]

The red chord is a diameter of the circle, so the length of the blue arc is half the circle's circumference.

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4 0
3 years ago
three sets of the sum of a number and four are added to the sum of seven times the same number and thirteen
almond37 [142]

The algebraic expression for given statement is: 10x + 25 or 3(x + 4) + (7x + 13)

<em><u>Solution:</u></em>

Given the statement:

Three sets of a sum of a number and four are added to the sum of seven times the same number and thirteen

Let us first understand the given statement,

Let the number be "x"

" sum of a number and four" means x + 4

"Three sets of a sum of a number and four" translated to 3(x + 4)

"sum of seven times the same number and thirteen" means 7x + 13

<em><u>Thus the algebraic expression for given statement is:</u></em>

3(x+4)+(7x + 13)

<em><u>Using distributive property in above expression</u></em>

a(b+c) = ab + bc

Therefore,

3(x+4)+(7x + 13) = 3x + 12 + 7x + 13

<em><u>Combine the like terms</u></em>

3(x+4)+(7x + 13) = 10x+25

Thus the required expression for given statement is: 10x + 25 or 3(x + 4) + (7x + 13)

7 0
2 years ago
Can someone like do my homeowkr for me? im lazy and it was due yesterday
sweet [91]

Answer:

you can just look it up

Step-by-step explanation:

7 0
2 years ago
Help?,?,?,?.!.??.?.?.?.?.?.
DaniilM [7]

Answer:

Step-by-step explanation:

b(a + 1) + a = b*a + b + a = ab + b + a

1) b(2a +1 ) = b*2a + b*1 = 2ab + b  Not equivalent.

2)a + (a +1)*b = a + ab+ b     Equivalent

3) (a +1)(b+ a) = a*(b +a) + 1*(b+a) = ab+ a² +b + a  Not equivalent.

4) (a + 1)b + a = ab+ b + a   Equivalent

5) a + b(a+1) = a +ab + b Equivalent

6) a + (a +1) + b = a + a + 1 + b = 2a + 1 +b  Not equivalent.

7) a(b +1) + b = ab + a + b  Equivalent

5 0
3 years ago
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