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eimsori [14]
3 years ago
9

Find a possible value of b. 5x2 - bx - 8​

Mathematics
1 answer:
pychu [463]3 years ago
3 0

Answer:

Step-by-step explanation:

Without more input from you, it's hard to find an exact value for b.  However, b may take on a large range of values.  b = 10 and b = -3 (chosen arbitrarily) are acceptable choices.

Take a look at the quadratic formula.  The discriminant is b^2 - 4ac.  There is nothing about this equation that restricts or forbids the use of any value of b.

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Step-by-step explanation:

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3 years ago
Describe how (2 cubed) (2 superscript negative 4) can be simplified. Multiply the bases and add the exponents. Then find the rec
charle [14.2K]

Add the exponents and keep the same base. Then reciprocal it and change the sign of the exponent. Then the value of the exponent expression is 0.5.

<h3>What is an exponent?</h3>

Exponential notation is the form of mathematical shorthand which allows us to write complicated expressions more succinctly. An exponent is a number or letter is called the base. It indicates that the base is to raise to a certain power. X is the base and n is the power.

The exponent expression is 2³ × 2⁻⁴ can be simplified.

Add the exponents and keep the same base. Then we have

2³ × 2⁻⁴  = 2⁽³⁻⁴⁾

2³ × 2⁻⁴  = 2⁻¹

Then find the reciprocal and change the sign of the exponent.

2^3* 2^{-4} = 2^{-1}\\\\2^3* 2^{-4} = \dfrac{1}{2}\\\\2^3* 2^{-4} = 0.5

The value is 0.5.

More about the exponent link is given below.

brainly.com/question/5497425

7 0
2 years ago
Find the equation of the line shown.
USPshnik [31]

Answer:

increasing straight line not passing through origin

5 0
3 years ago
Find the values of the variables in the parallelogram. The diagram is not to scale.
rusak2 [61]
X=29
y=180-29-102=49
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6 0
3 years ago
Name the line of reflection used to map each pre-image to its image.<br> Please help
maks197457 [2]

Answer:

Step-by-step explanation:

From the picture attached,

9). When pre-image KLMN is a reflected across x = -2, we get image K'L'M'N'.

    Therefore, line of reflection will be x = -2

10). In this picture line of reflection which passes through origin (0, 0) and slope = 1 will be,

y = x.

11). Since, all the points of image and preimage points are equidistant from x-axis, line of reflection will be x-axis or y = 0.

12). Line passing through midpoint of the line joining BB' will be the line of reflection.

Coordinates of B → (5, 3)

Coordinates of B' → (5, 7)

Coordinates of BB' → (\frac{5+5}{2},\frac{3+7}{2}) → (5, 5)

Therefore, line of reflection will be y = 5.

13). Coordinates of G → (2, 5)

     Coordinates of G' → (-2, 5)

     Midpoint joining the segment GG' → (\frac{2-2}{2},\frac{5+5}{2}) → (0, 5)

     Therefore, line of reflection → x = 0

14). Line of reflection passing through (0, 0) and slope = -1

     y = -x

3 0
3 years ago
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