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77julia77 [94]
3 years ago
10

20=6x+14 answer 0=6 true or false ?????

Mathematics
2 answers:
Roman55 [17]3 years ago
4 0

Hey there!

Let's solve the equation.

20=6x+14

Subtract 14 from both sides.

6=6x

Divide 6 on both sides.

x=1

This is false.

I hope this helps!

~kaikers

Bogdan [553]3 years ago
4 0

[|] Answer [|]

\boxed{False}

[|] Explanation [|]

20 = 6x + 14

0 = 6

True or False

_________________

_________________

- Solve For X -

Switch Sides:

6x + 14 = 20

Subtract 14 From Both Sides:

6x + 14 - 14 = 20 - 14

Simplify:

6x = 6

Divide Both Sides By 6:

\frac{6x}{6} \ = \frac{6}{6}

Simplify:

X = 1

__________________

__________________

X \boxed{Is \ **NOT**} Equal To 6

\boxed{[|] \ Eclipsed \ [|]}

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\bf \begin{array}{llll}
tan(\alpha)=-\cfrac{80}{15}\qquad II\\\\
x=-15\\
y=8\\
r=17
\end{array} \qquad \qquad 
\begin{array}{llll}
cos(\beta)=\cfrac{5}{6}\qquad I\\\\
x=5\\
y=\sqrt{11}\\
r=6
\end{array}\\\\
-----------------------------\\\\
sin({{ \alpha}} + {{ \beta}})=sin({{ \alpha}})cos({{ \beta}}) + cos({{ \alpha}})sin({{ \beta}})
\\\\\\
sin({{ \alpha}} + {{ \beta}})=\cfrac{8}{17}\cdot \cfrac{5}{6}+\cfrac{-15}{17}\cdot \cfrac{\sqrt{11}}{6}\implies \cfrac{40-15\sqrt{11}}{102}



\bf cos({{ \alpha}} + {{ \beta}})= cos({{ \alpha}})cos({{ \beta}})- sin({{ \alpha}})sin({{ \beta}})
\\\\\\
\cfrac{-15}{17}\cdot \cfrac{5}{6}-\cfrac{8}{17}\cdot \cfrac{\sqrt{11}}{6}\implies \cfrac{-75-8\sqrt{11}}{102}





\bf tan({{ \alpha}} + {{ \beta}}) = \cfrac{tan({{ \alpha}})+ tan({{ \beta}})}{1- tan({{ \alpha}})tan({{ \beta}})}
\\\\\\
tan({{ \alpha}} + {{ \beta}}) = \cfrac{-\frac{8}{15}+\frac{\sqrt{11}}{5}}{1-\left( -\frac{8}{15}\cdot \frac{\sqrt{11}}{5} \right)}\implies 
\cfrac{\frac{-8+3\sqrt{11}}{15}}{1+\frac{8\sqrt{11}}{75}}
\\\\\\
tan({{ \alpha}} + {{ \beta}}) =\cfrac{\frac{-8+3\sqrt{11}}{15}}{\frac{75+8\sqrt{11}}{75}}\implies \cfrac{-8+3\sqrt{11}}{15}\cdot \cfrac{75}{75+8\sqrt{11}}
\\\\\\


\bf tan({{ \alpha}} + {{ \beta}}) =\cfrac{-8+3\sqrt{11}}{1}\cdot \cfrac{3}{75+8\sqrt{11}}\implies \cfrac{15\sqrt{11}-40}{75+8\sqrt{11}}
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