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Mkey [24]
3 years ago
10

8

Mathematics
1 answer:
allsm [11]3 years ago
4 0

Answer:

Jennifer has 7 quarters

Step-by-step explanation:

<u><em>The correct question is</em></u>

Jennifer has $ 3.51 in change in her  piggy bank. The change consists of 51 coins inducing pennies, nickels and  quarters. If there are 3 times as many nickels as pennies, how many quarters  does she have?

Remember that

1\ penny=\$0.01\\1\ nickel=\$0.05\\1\ quarter=\$0.25

Let

x ----> the number of pennies

y ---> the number of nickels

z ---> the number of quarters

we know that

x+y+z=51 -----> equation A

0.01x+0.05y+0.25z=3.51 ----> equation B

y=3x ---> equation C

substitute equation C in equation A and equation B

x+3x+z=51

4x+z=51 -----> equation D

0.01x+0.05(3x)+0.25z=3.51

0.16x+0.25z=3.51 ----> equation E

we have

4x+z=51 -----> equation D

0.16x+0.25z=3.51 ----> equation E

Solve the system of equations D and E by graphing

Remember that the solution is the intersection point both graphs

The solution is the point (11,7)

x=11,z=7

see the attached figure

Find the value of y

y=3(11)=33

so

The number of pennies is 11

The  number of nickels is 33

The number of quarters is 7

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Savatey [412]

Answer:

z=40 degrees

x=90 degrees

y=40 degrees

Step-by-step explanation:

To solve z you know that 50+90+z= 180 degrees. So z equals 40. To solve x you subtract 90 from 180 to get 90 degrees. To solve you add 50+x+y. You know that x= 90. You would add the angles together to get 180 degrees. 50+90=140 and 180-140 equals 40. Sorry if i'm wrong.

6 0
3 years ago
3.541 and 41 is repeated, what would it be as a simplified fraction?
qwelly [4]

Answer: 3.5

Step-by-step explanation: Because the 4 and 1 aren’t big enough to change the 5 to go up the final answer would be 3.5 but if the 4 were to be a 5 or a number higher than the 5 would change to a 6.

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Find the domain and range of the function:<br> f(x) =5-x-3 to the square root<br> Domain:<br> Range:
mario62 [17]
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Range: ( -infinity, infinity ) , { y|y € R }
6 0
3 years ago
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Makovka662 [10]

Answer:

Use M a t h W a y

Step-by-step explanation:

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3 years ago
A 0.45-mm-wide slit is illuminated by light of wavelength 590 nm. What is the width (in mm) of the central maximum on a screen 1
Hitman42 [59]

Answer:

w = \frac{2(590x10^{-9}) (1.5m)}{0.45x10^{-3}}=3.93 x10^{-3} m

And if we convert this into mm we got:

w= 3.93 x10^{-3} m *\frac{1000mm}{1 m}= 3.93 mm

Step-by-step explanation:

For this case we have the following info givenL

\lambda = 590 nm = 590 x10^{-9}m represent the wavelength

s = 0.45 mm *\frac{1m}{1000 mm}= 0.45x10^{-3} m represent the width of the single slit

L = 1.5 m represent the longitude

And we want to find the maximum width of the central maximum in mm, so we can use the following formula:

w s = 2 \lambda L

And if we solve for w the width we got:

w = \frac{2\lambda L}{s}

And replacing we got:

w = \frac{2(590x10^{-9}) (1.5m)}{0.45x10^{-3}}=3.93 x10^{-3} m

And if we convert this into mm we got:

w= 3.93 x10^{-3} m *\frac{1000mm}{1 m}= 3.93 mm

6 0
3 years ago
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