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Luden [163]
3 years ago
6

point G is the center of small circle. Point X is the center of the large circle. Points GH and ask her all online segment GX. W

hat would be the area of the new circle that has line segment GX as its diameter? 16 pounds in 1 million square, 36 by centimeter square, 49 price and neither square, 98 pie centimeter squared.

Mathematics
2 answers:
otez555 [7]3 years ago
8 0

Answer:

49

Step-by-step explanation:

It's right I promise

Korvikt [17]3 years ago
7 0

Answer:

49 pi cm 2

Step-by-step explanation:

Because the circle is dilated and then you have to use the ratio r= area over pi

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What multiplies to 3025 and adds to -111?
sattari [20]
The numbers 55 and 55.
3 0
3 years ago
Help finding the area
snow_lady [41]

Answer:

The answer is 49 in^2.

Step-by-step explanation:

The area of the triangle is 1/2* perpendicular height * horizontal length.

The horizontal length is 14 in, while the perpendicular height is 7 in.

The area of the triangle is 1/2* 7 in * 14 in = 49 in^2

6 0
3 years ago
Does the equation x^2+y=144 define y as a function of x?
11Alexandr11 [23.1K]

The given equation is

x^2 + y = 144

First we solve for y, and for that, we have to islolate y, that is

y= 144-x^2

And it pass the vertical line test. So here y is a function of x .

So we can define the given equation as y as a function of x .

8 0
3 years ago
2. Evaluate the expression for q = 2 6​
GenaCL600 [577]

Answer:

12

Step-by-step explanation:

This may not be intirely correct because you said q = 2 6. I think that means 2 times 6.

Anyways

2 x 6 = 12

⇒ q = 12

5 0
3 years ago
Find a cubic function f(x) = ax3 + bx2 + cx + d that has a local maximum value of 4 at x = −3 and a local minimum value of 0 at
Vinvika [58]
The formula is f(x) = a x ^ 3 + b x ^ 2 + c x  + d 
f '(x) = 3ax^2 + 2bx + c. 
f(- 3) = 3 ==> - 27a + 9b - 3c + d = 3 
f '(- 3) = 0 (being a most extreme) ==> 27a - 6b + c = 0. 
f(1) = 0 ==> a + b + c + d = 0 
f '(1) = 0 (being a base) ==> 3a + 2b + c = 0. 
- 
Along these lines, we have the four conditions 
- 27a + 9b - 3c + d = 3 
a + b + c + d = 0 
27a - 6b + c = 0 
3a + 2b + c = 0 
Subtracting the last two conditions yields 24a - 8b = 0 ==> b = 3a. 
Along these lines, the last condition yields 3a + 6a + c = 0 ==> c = - 9a. 
Consequently, we have from the initial two conditions: 
- 27a + 9(3a) - 3(- 9a) + d = 3 ==> 27a + d = 3 
a + 3a - 9a + d = 0 ==> d = 5a. 
Along these lines, a = 3/32 and d = 15/32. 
==> b = 9/32 and c = - 27/32. 
That is, f(x) = (1/32)(3x^3 + 9x^2 - 27x + 15).
8 0
3 years ago
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