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3 years ago

81 ÷ (__÷ 4) =9 evaluate the numeric expression

Mathematics

1 answer:

Dafna11 [192]3 years ago

6 0

36 is the answer. 36/4=9 81/9=9

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-1/2+c=31/4 A. C=33/4 B. C=8 C. 29/4 D. 7

kkurt [141]

Answer:

Step-by-step explanation:

-1/2+c=31/4

-1/2+c+1/2=31/4+1/2

c=33/4

4 0

3 years ago

HELP ONLY ANSWER QUESTION 10. THANKS

swat32

X - 5 = x^2

i) 0 - 5 = -5^2 = 25

ii) 4 - 5 = -1^2 = 1

iii) -4 - 5 = -9^2 = 81

5 0

3 years ago

I need help with this!

AleksAgata [21]

9514 1404 393

Answer:

64.6

Step-by-step explanation:

One standard deviation is 4.3. Then +2 standard deviations is ...

(+2)(4.3) = +8.6

This amount added to the mean gives ...

56 +8.6 = 64.6 . . . . +2σ from the mean

5 0

2 years ago

Find the slope of the line that passes through the pair of points

professor190 [17]

$Slope= \frac{y_2-y_1}{x_2-x_1} = \frac{-\frac{9}{2} - (-1)}{-2- (-\frac{5}{3})}=\frac{ - \frac{9}{2} + 1}{-2 + \frac{5}{3}} \\= \frac{ - \frac{7}{2}}{ - \frac{1}{3}} \\= \frac{ - \frac{7}{2}\cdot6}{ - \frac{1}{3}\cdot6} \\=\frac{-21}{ -2} \\ =\boxed{\bf{ \frac{21}{2}}}$

So... none of your answers are correct. The correct answer is 21/2.

6 0

3 years ago

Write an equation in slope-intercept form for the line that passes through the point ( -1 , -2 ) and is perpendicular to the l

mamaluj [8]

The equation in slope-intercept form for the line that passes through the point ( -1 , -2 ) and is perpendicular to the line − 4 x − 3 y = − 5 is $y = \frac{3}{4}x - \frac{5}{4}$

Solution:

The slope intercept form is given as:

y = mx + c ----- eqn 1

Where "m" is the slope of line and "c" is the y - intercept

Given that the line that passes through the point ( -1 , -2 ) and is perpendicular to the line − 4 x − 3 y = − 5

Given line is perpendicular to − 4 x − 3 y = − 5

− 4 x − 3 y = − 5

-3y = 4x - 5

3y = -4x + 5

$y = \frac{-4x}{3} + \frac{5}{3}$

On comparing the above equation with eqn 1, we get,

$m = \frac{-4}{3}$

We know that product of slope of a line and slope of line perpendicular to it is -1

$\frac{-4}{3} \times \text{ slope of line perpendicular to it}= -1\\\\\text{ slope of line perpendicular to it} = \frac{3}{4}$

Given point is (-1, -2)

Now we have to find the equation of line passing through (-1, -2) with slope $m = \frac{3}{4}$

Substitute (x, y) = (-1, -2) and m = 3/4 in eqn 1

$-2 = \frac{3}{4}(-1) + c\\\\-2 = \frac{-3}{4} + c\\\\c = - 2 + \frac{3}{4}\\\\c = \frac{-5}{4}$

$\text{ substitute } c = \frac{-5}{4} \text{ and } m = \frac{3}{4} \text{ in eqn 1}$

$y = \frac{3}{4} \times x + \frac{-5}{4}\\\\y = \frac{3}{4}x - \frac{5}{4}$

Thus the required equation of line is found

8 0

2 years ago