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Tresset [83]
4 years ago
7

Jermaine wants to know how fast he is traveling in a school bus, but he cannot see the speedometer. He records that the bus trav

els 1 mile in 75 seconds. How fast is Jermaine traveling in miles per hour?
Mathematics
1 answer:
Advocard [28]4 years ago
8 0
<h3>Answer:</h3>

48 mph

<h3>Explanation:</h3>

The rate in miles per second can be converted to the rate in miles per hour by multiplying by the number of seconds in an hour:

\dfrac{1\,mi}{75\,s}\cdot\dfrac{3600\,s}{1\,h}=\dfrac{3600\,mi}{75\,h}=48\,mi/h

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Sara pays $2,120 in bills each month. Her monthly income is $2,960. What is Sara's disposable income?
Wittaler [7]
Saras disposable income is $840
3 0
3 years ago
Read 2 more answers
What is the value of the x-coordinate of the vertex of the function shown
lakkis [162]

The answer is x=-2

As you could see, this is a factored function.

The un-factored version is x^2+4x-12

-b/2a=x

-4/2=-2= x of vertex

7 0
3 years ago
determine the value of x for which r parallels s. then find the measure of angle 1 and the measure of angle 2measure angle 1= 50
Maslowich

According to the picture, angles 1 and 2 have the same measure because they are corresponding angles. Make equal both expressions for 1 and 2 and find x.

\begin{gathered} 50-2x=110-42x \\ 42x-2x=110-50 \\ 40x=60 \\ x=\frac{60}{40} \\ x=\frac{3}{2} \end{gathered}

x is 3/2. Replace this value in both expression to find the measure of each angle.

\begin{gathered} \measuredangle1=50-2x \\ \measuredangle1=50-2(\frac{3}{2}) \\ \measuredangle1=50-3 \\ \measuredangle1=47 \\ \measuredangle2=110-42x \\ \measuredangle2=110-42(\frac{3}{2}) \\ \measuredangle2=110-63 \\ \measuredangle2=47 \end{gathered}

The measure of these angles is 47°

7 0
2 years ago
Ten thousand raffle tickets are sold for $1 each. One first prize of $2000, 4 second prizes of $700 each, and 8 third prizes of
Nina [5.8K]

Answer:

72 cents.

Step-by-step explanation:

The expected winnings is the amount times the probability that you will get that amount.

2,000 * (1/10,000) = 2,000 / 10,000 = 2 / 10 = 0.2.

700 * (4 / 10,000) = 2,800 / 10,000 = 28 / 100 = 0.28.

300 * (8 / 10,000) = 2,400 / 10,000 = 24 / 100 = 0.24.

0.2 + 0.28 + 0.24 = 0.72.

Hope this helps!

4 0
3 years ago
Given f(x)=cos c and g(x)=cot x, what are the domain and range of f(g(x))?
ololo11 [35]

Answer:

Alternative C is the correct answer

Step-by-step explanation:

The first step is to determine the composite function;

f[g(x)]

f[g(x)]=cos[cot(x)]

We then employ a graphing utility to determine the range and the domain of the new function.

The range is the set of y-values for which the function is defined. In this case it is;

[-1,1]

On the other hand, the domain refers to the set of the x-values for which the function is real and defined. In this case; it is the set of real numbers x except x does not equal npi for all integers n.

8 0
3 years ago
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