Answer:
A. a reflection over the x-axis and then a reflection over the y-axis
and
B. a reflection over the y-axis and then a reflection over the x-axis
Step-by-step explanation:
Answer:
Solved for n, <em>n = 2p</em>
Step-by-step explanation:
14n + 6p - 8n = 18p
6n + 6p = 18p
6n = 12p
n = 2p
B I think wait for another answer to compare
10(h)+5(h)+7, because 10 and 15 are charged per a hour, so they have a h(house). 7 dollars is a fee that you only pay once. I hope this helps :)
What is the solution to 3 + 4e^x+1 = 11?
Solution:
![3+4e^{x+1}=11](https://tex.z-dn.net/?f=3%2B4e%5E%7Bx%2B1%7D%3D11)
To solve for x, Let us subtract 3 from both sides
![3+4e^{x+1}-3=11-3](https://tex.z-dn.net/?f=3%2B4e%5E%7Bx%2B1%7D-3%3D11-3)
![0+4e^{x+1}=8](https://tex.z-dn.net/?f=0%2B4e%5E%7Bx%2B1%7D%3D8)
![4e^{x+1}=8](https://tex.z-dn.net/?f=4e%5E%7Bx%2B1%7D%3D8)
Let us divide by 4 on both sides
![\frac{4e^{x+1}}{4} =\frac{8}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B4e%5E%7Bx%2B1%7D%7D%7B4%7D%20%3D%5Cfrac%7B8%7D%7B4%7D)
![\frac{1e^{x+1}}{1} =\frac{2}{1}](https://tex.z-dn.net/?f=%5Cfrac%7B1e%5E%7Bx%2B1%7D%7D%7B1%7D%20%3D%5Cfrac%7B2%7D%7B1%7D)
![e^{x+1} =2](https://tex.z-dn.net/?f=e%5E%7Bx%2B1%7D%20%3D2)
Let us take ln on both sides
![ln (e^{x+1}) =ln(2)](https://tex.z-dn.net/?f=ln%20%28e%5E%7Bx%2B1%7D%29%20%3Dln%282%29)
So, x+1=ln(2)
To solve for x, Let us subtract 1 from both sides
x+1-1=ln(2) -1
x+0=ln(2)-1
x= ln(2) -1
Answer: Option (A)
x=ln(2)-1