Answer:An initial condition is an extra bit of information about a differential equation that tells you the value of the function at a particular point. Differential equations with initial conditions are commonly called initial value problems.
The video above uses the example
{
d
y
d
x
=
cos
(
x
)
y
(
0
)
=
−
1
to illustrate a simple initial value problem. Solving the differential equation without the initial condition gives you
y
=
sin
(
x
)
+
C
.
Once you get the general solution, you can use the initial value to find a particular solution which satisfies the problem. In this case, plugging in
0
for
x
and
−
1
for
y
gives us
−
1
=
C
, meaning that the particular solution must be
y
=
sin
(
x
)
−
1
.
So the general way to solve initial value problems is: - First, find the general solution while ignoring the initial condition. - Then, use the initial condition to plug in values and find a particular solution.
Two additional things to keep in mind: First, the initial value doesn't necessarily have to just be
y
-values. Higher-order equations might have an initial value for both
y
and
y
′
, for example.
Second, an initial value problem doesn't always have a unique solution. It's possible for an initial value problem to have multiple solutions, or even no solution at all.
Explanation:
You should make sure no one is looking and make sure you have protection
They may not have enough money for the bill at the time, and its easier to pay for insurance for unseen medical procedures.
Hello.
The benefits of using presentations to organize and deliver information are: it keeps things in order, keeps peoples attention longer, and it looks more professional.
The indices of the internal array elements that hold the remaining elements is c) 2 to 4
<h3>Calculations and Parameters:</h3>
For us to create a capacity of 10 for the queue, we would enqueue:
We would create a queue of capacity 10:
<h3>Queue q(10);</h3>
We add elements/enqueue 5 elements to the queue :
- q.queueEnqueue(10);
- q.queueEnqueue(5);
- q.queueEnqueue(8);
- q.queueEnqueue(9);
- q.queueEnqueue(2);
Printing this would give:
q. queueDisplay()
10, 5, 8, 9, 2
Next, we would remove elements/dequeue 2 elements from the queue :
q. queuedequeue();
q. queuedequeue();
Printing it would be:
q. queueDisplay()
8 ,9, 2
Observing this, the deletion/dequeue starts from the front/first index.
The remaining indices of the internal array elements are: 2, 3, 4 or 2 to 4
Read more about arrays and enqueue here:
brainly.com/question/24188935
#SPJ1
