<u>Answer:</u> The value of 
for the reaction is 1051.93 J/K
<u>Explanation:</u>
Entropy change is defined as the difference in entropy of all the product and the reactants each multiplied with their respective number of moles.
The equation used to calculate entropy change is of a reaction is:
![\Delta S^o_{rxn}=\sum [n\times \Delta S^o_{(product)}]-\sum [n\times \Delta S^o_{(reactant)}]](https://tex.z-dn.net/?f=%5CDelta%20S%5Eo_%7Brxn%7D%3D%5Csum%20%5Bn%5Ctimes%20%5CDelta%20S%5Eo_%7B%28product%29%7D%5D-%5Csum%20%5Bn%5Ctimes%20%5CDelta%20S%5Eo_%7B%28reactant%29%7D%5D)
For the given chemical reaction:
The equation for the entropy change of the above reaction is:
![\Delta S^o_{rxn}=[(2\times \Delta S^o_{(Cr_2O_3(s))})]-[(4\times \Delta S^o_{(Cr(s))})+(3\times \Delta S^o_{(O_2(g))})]](https://tex.z-dn.net/?f=%5CDelta%20S%5Eo_%7Brxn%7D%3D%5B%282%5Ctimes%20%5CDelta%20S%5Eo_%7B%28Cr_2O_3%28s%29%29%7D%29%5D-%5B%284%5Ctimes%20%5CDelta%20S%5Eo_%7B%28Cr%28s%29%29%7D%29%2B%283%5Ctimes%20%5CDelta%20S%5Eo_%7B%28O_2%28g%29%29%7D%29%5D)
We are given:
Putting values in above equation, we get:
![\Delta S^o_{rxn}=[(2\times (881.2))]-[(4\times (23.77))+(3\times (205.13))]\\\\\Delta S^o_{rxn}=1051.93J/K](https://tex.z-dn.net/?f=%5CDelta%20S%5Eo_%7Brxn%7D%3D%5B%282%5Ctimes%20%28881.2%29%29%5D-%5B%284%5Ctimes%20%2823.77%29%29%2B%283%5Ctimes%20%28205.13%29%29%5D%5C%5C%5C%5C%5CDelta%20S%5Eo_%7Brxn%7D%3D1051.93J%2FK)
Hence, the value of for the reaction is 1051.93 J/K
Answer:
The amount of heat released when 50 g of water cooled from 20°C to 10°C will be equal to - 2093 J.
Explanation:
Given data:
Mass of water = 50 g
Initial temperature= T1 = 20°C
Final temperature= T2 = 10°C
Specific heat of water= c = 4.186 J/g. °C
Amount of heat released = Q= ?
Solution:
Formula:
Q = m. C. ΔT
ΔT = T2 - T1
ΔT = 10°C - 20°C
ΔT = -10°C
Now we will put the values in formula.
Q = m. C. ΔT
Q = 50 g . 4.186 J/g. °C . -10°C
Q = - 2093 J
The amount of heat released when 50 g of water cooled from 20°C to 10°C will be equal to - 2093 J.
The answer is C) Volume . Kilograms is a for of measurement for weight and mass is kinda like weight but mass doesnt change no matter the place or planet.
A buffer system usually will need a weak acid, like H2CO3, which is carbonic acid, and a strong base, and the only compound that could figure a fairly strong base among the options given is Na2CO3. NH3 and NaHCO3 are weak bases and HF is a strong acid. Therefore the best answer will be letter A
I don’t understand what the question is?
