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BartSMP [9]
4 years ago
15

Ethoxide ion is a base that can remove an acidic proton in an α-position to a carbonyl group. The resulting enolate ion is a nuc

leophile. What electrophilic site will it attack?
Chemistry
1 answer:
german4 years ago
4 0

Answer:

The electrophilic site that it will attack will be the carbonyl carbon

Explanation:

Assuming that in the solution there is excess of carbonyl group attached compound

As ethoxide ion is a strong base, it can remove an acidic proton in an α-position to a carbonyl group

The resulting compound will be an enolate ion and in enolate ion the centre of attacking will be the carbon and as there is negative charge on the carbon, it will get stabilized because of resonance and - I effect of carbonyl group

As the negative charge on the carbon can be stabilized by resonance, it will be a weak base when compared to ethoxide ion but it has more nucleophilic character when compared to ethoxide ion because in polar solvents there will be solvation effect on ethoxide ion

The electrophilic site is the position where there will be partial positive charge and in this case the electrophilic site will be the carbon in carbonyl group attached compound because of - I effect of sp_{2} oxygen it will gain partial positive charge

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In the equation below, which of the following is true?<br><br> 2Fe + 6HBr yields 2FeBr3 + 3H2
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8 0
3 years ago
What evidence supports a conservation law?
True [87]

Answer:

The answer is B.

Explanation:

The law of conservation of mass states that mass in an isolated system is neither created nor destroyed by chemical reactions or physical transformations.

According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants.

The law of conservation of mass is useful for a number of calculations and can be used to solve for unknown masses, such the amount of gas consumed or produced during a reaction.

3 0
4 years ago
If 50.0 g of KCl reacts with 50.0 g of O2 to produce KClO3 according to the following equation, how many grams of KClO3 will be
Sliva [168]

Answer:

A. 82.2g of KClO3

B. Word equation:

50g of KCl react with 50g of O2 to produce 82.2g of KClO3

C. Formula equation:

2KCl + 3O2 —> 2KClO3

Explanation:

The balanced equation for the reaction. This is given below:

2KCl + 3O2 —> 2KClO3

Next, we shall determine the masses of KCl and O2 that reacted and the mass of KClO3 produced from the balanced equation. This is illustrated below:

Molar Mass of KCl = 39 + 35.5 = 74.5g/mol

Mass of KCl from the balanced equation = 2 x 74.5 = 149g

Molar Mass of O2 = 16x2 = 32g/mol

Mass of O2 from the balanced equation = 3 x 32 = 96g

Molar Mass of KClO3 = 39 + 35.5 + (16x3) = 122.5g/mol

Mass of KClO3 from the balanced equation = 2 x 122.5 = 245g

Summary:

From the balanced equation above:

149g of KCl reacted.

96g of O2 reacted.

245g of KCl were produced.

Next, we shall determine the limiting reactant. This is illustrated below:

From the balanced equation above,

149g of KCl reacted with 96g of O2.

Therefore, 50g of KCl will react with = (50 x 96)/149 = 32.21g of O2.

Since a lesser mass of O2 ( i.e 32.21g) than what was given (i.e 50g) is needed to react completely with 50g of KCl, therefore, KCl is the limiting reactant and O2 is the excess reactant.

A. Determination of the mass of KClO3 produced from the reaction.

In this case the limiting reactant will be used.

From the balanced equation above,

149g of KCl reacted To produce 245g of KClO3.

Therefore, 50g of KCl will react to produce = (50 x 245)/149 = 82.2g of KClO3.

Therefore, 82.2g of KClO3 is produced from the reaction.

B. Word equation:

50g of KCl react with 50g of O2 to produce 82.2g of KClO3.

C. Formula equation:

2KCl + 3O2 —> 2KClO3

4 0
4 years ago
Which of the following is not an indication of a chemical reaction?
amm1812
Formation of a precipitate
4 0
4 years ago
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