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olga2289 [7]
3 years ago
15

If 7.400 g of C6H6 is burned and the heat produced from the burning is added to 5691 g of water at 21 °C, what is the final temp

erature of the water?
Chemistry
1 answer:
Andru [333]3 years ago
8 0
In your problems the possible solution is this one:

<span><span>F<span>fr</span></span>=<span>μk</span><span>FN</span>=<span>μk</span>mg</span><span>0.5(50000kg)(−9.8<span>m<span>s2</span></span>)</span><span>=−245000N</span> <span>a=F/m</span><span>−245000N/50000kg</span><span>=−4.9<span>m<span>s2</span></span></span><span>t=<span><span>v−<span>v0</span></span>a</span></span><span><span>0−10<span>ms</span></span><span>−4.9<span>m<span>s2</span></span></span></span><span><span>=2s

I hope you understand and satisfied with my answer</span></span>
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Answer:

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Explanation:

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3 years ago
Suppose a compound is involved in three different reactions denoted R1, R2, and R3. Tripling the concentration of this reactant
pickupchik [31]

Answer:

The order of reaction is as follows, R1 = 1; R2 = 2; R3 = 0

Explanation:

The rate of a chemical reaction is the number of moles of reactants consumed per unit time or the number of moles of products formed per unit. the rate of a chemical reaction is affected by the concentration of reactants

The relationship between the rate of a chemical reaction and the concentration of its reactants is given by the rate law or equation.

Generally, the rate equation is given as;

Rate = k[A]ᵃ[B]ᵇ..., where k = rate constant which is independent of concentration of the reactants, [A] = concentration of reactant A, a = order of reaction A, [B] = concentration of reaction B, b = order of reaction B.

For the given reactions R1, R2 and R3

For R1; rate = 3, Concentration = 3[A]

3 = k[A]3ˣ

3¹ = k[A]3ˣ

Since rate is proportional to concentration, therefore, the order of reaction, x = 1

For R2; rate = 9, Concentration = 3[A]

9 = k[A]3ˣ

3² = k[A]3ˣ

Since rate is proportional to concentration, therefore, the order of reaction, x = 2

For R1; rate = 1, Concentration = 3[A]

1 = k[A]3ˣ

3⁰ = k[A]3ˣ

Since rate is proportional to concentration, therefore, the order of reaction, x = 0

Therefore, the order of reaction is as follows, R1 = 1; R2 = 2; R3 = 0

6 0
3 years ago
Find How many joules of heat energy are needed to raise the temperature of 10grams of Aluminum from 20*C to 40*C. If the specifi
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Explanation:

the answer and the working out is shown above, hope it helps.

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A sample of gas contains 0.1800 mol of CO(g) and 0.1800 mol of NO(g) and occupies a volume of 23.2 L. The following reaction tak
baherus [9]

Answer:

The volume of the sample is 17.4L

Explanation:

The reaction that occurs requires the same amount of CO and NO. As the moles added of both reactants are the same you don't have any limiting reactant. The only thing we need is the reaction where 4 moles of gases (2mol CO + 2mol NO) produce 3 moles of gases (2mol CO2 + 1mol N2). The moles produced are:

0.1800mol + 0.1800mol reactants =

0.3600mol reactant * (3mol products / 4mol reactants) = 0.2700 moles products.

Using Avogadro's law (States the moles of a gas are directly proportional to its pressure under constant temperature and pressure) we can find the volume of the products:

V1n2 = V2n1

<em>Where V is volume and n moles of 1, initial state and 2, final state of the gas</em>

Replacing:

V1 = 23.2L

n2 = 0.2700 moles

V2 = ??

n1 = 0.3600 moles

23.2L*0.2700mol = V2*0.3600moles

17.4L = V2

<h3>The volume of the sample is 17.4L</h3>
8 0
3 years ago
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