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Fynjy0 [20]
2 years ago
12

While heating up a 25 gram sample of concrete (specific heat = 0.210-cal/g°C), your initial tempărature is room temperature (25°

C), you found that the substance gained 305 calories. What was the final temperature of your sample?
**Round your answer to the nearest 0.1**

I got 83.1 but I just want to check it
Chemistry
1 answer:
Lana71 [14]2 years ago
7 0

Answer:

Final temperature  = 83.1 °C

Explanation:

Given data:

Mass of concrete = 25 g

Specific heat capacity = 0.210 cal/g. °C

Initial temperature = 25°C

Calories gain = 305 cal

Final temperature = ?

Solution:

Q = m. c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = T2 - T1

305 cal = 25 g ×0.210 cal/g.°C × T2 -  25°C

305 cal = 5.25cal/°C × T2 -  25°C

305 cal / 5.25cal/°C = T2 -  25°C

58.1 °C = T2 -  25°C

T2 = 58.1 °C + 25°C

T2 = 83.1 °C

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Answer:

Hope this helps

Explanation:

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3 years ago
what is the number of each type of atom on the right side of the equation 2Na3PO4(aq)+2CoCl2(aq)→2Co3(PO4)2(s)+6NaCl(aq)
Andre45 [30]

6 atoms of Cobalt.

4 atoms to Phosphate (PO4).

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If the compound has parenthesis, then the subscript within the parenthesis remains untouched and does not affect the atoms.

Basically, to calculate the atoms is multiply the coefficient (number in front of the atom) by the subscript attached to the atom. If it's a compound such as Co3PO4, then make sure the coefficient affects the second atom as well.

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3 0
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What acid and base form Ca3(PO4)2
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3 0
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Question 33 Saved
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The third option

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Given 50.0 grams of Strontium, find grams of Phosphorus required for complete reaction
Sveta_85 [38]

Answer:

                     Mass = 11.78 g of P₄

Explanation:

                     The balance chemical equation is as follow:

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Step 1: Calculate moles of Sr as;

Moles = Mass / M/Mass

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Step 2: Find moles of P₄ as;

According to equation,

6 moles of Sr reacted with  =  1 mole of P₄

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Solving for X,

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Mass = 0.0952 mol × 123.89 g/mol

Mass = 11.78 g of P₄

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2 years ago
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