Answer: A
Step-by-step explanation:
The answer is choice A since it has the rise and run of 2/3.
Answer and explanation:
There are six main trigonometric ratios, namely: sine, cosine, tangent, cosecant, secant, cotangent.
Those ratios relate two sides of a right triangle and one angle.
Assume the following features and measures of a right triangle ABC
- right angle: B, measure β
- hypotenuse (opposite to angle B): length b
- angle C: measure γ
- vertical leg (opposite to angle C): length c
- horizontal leg (opposite to angle A): length a
- angle A: measure α
Then, the trigonometric ratios are:
- sine (α) = opposite leg / hypotenuse = a / b
- cosine (α) = adjacent leg / hypotenuse = c / b
- tangent (α) = opposite leg / adjacent leg = a / c
- cosecant (α) = 1 / sine (α) = b / a
- secant (α) = 1 / cosine (α) = b / c
- cotangent (α) = 1 / tangent (α) = c / b
Then, if you know one angle (other than the right one) of a right triangle, and any of the sides you can determine any of the other sides.
For instance, assume an angle to be 30º, and the lenght of the hypotenuse to measure 5 units.
- sine (30º) = opposite leg / 5 ⇒ opposite leg = 5 × sine (30º) = 2.5
- cosine (30º) = adjacent leg / 5 ⇒ adjacent leg = 5 × cosine (30º) = 4.3
Thus, you have solved for the two unknown sides of the triangle. The three sides are 2.5, 4.3, and 5.
Answer:
4.77
Step-by-step explanation:
because Circumference can be found with this equation
C = 2piR
we need to plug in 15 for Circumference and solve for its radius or R.
15 = 2piR
15/2pi = R
but we need diameter which is 2R so we just need to multiply the answer by 2.
15/2pi × 2 = Diameter
15/pi = D
approximately = 4.77
Answer:
Combine the terms
300 + 70 = 370
5/10 + 8/100
Note that first, you must find common denominators. What you multiply to the denominator, you multiply to the numerator. Multiply 10 to the numerator and denominator of 5/10
(5/10)(10/10) = 50/100
50/100 + 8/100
Combine the terms
50/100 + 8/100 = 58/100
370 58/100 is another way to write it
The answer is 20,106 basically “B”
